Answer:
Explanation:
Mass of first cart M1=2.4kg
Velocity of first cart U1=4.1m/s
Mass of second cart M2=1.7kg
Second cart is initially at rest U2=0
After an instant, the velocity of the second cart is U2=-2.8m/s
Now after collision the two cart move together with the same velocity I.e inelastic collision
Using conservation of momentum
Momentum before collision, = momentum after collision
M1U1 + M2U2 = (M1+M2)V
2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V
9.84 - 4.76 = 4.1V
5.08=4.1V
V=5.08/4.1
V=1.24m/s
The momentum of the two cart at that instant is
M1U1+M2U2
2.4×4.1 + 1.7× -2.8
9.84 - 4.76
5.08kgm/s
So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s
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Answer:
a. 572Btu/s
b.0.1483Btu/s.R
Explanation:
a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.
From table A-3E, the specific heat of water is
, and the steam properties as, A-4E:

Using the energy balance for the system:

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s
b. Heat gained by the water is equal to the heat lost by the condensing steam.
-The rate of steam condensation is expressed as:

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R
Answer: 1925 joules
Explanation:
weight of man = 550 N
height climbed = 3.5m
Work = ?
Since, work is done when the man pulled his weight over the height; work is expressed as the product of weight and height climbed
i.e Workdone = 550N x 3.5m
= 1925 joules
Thus, the man did a work of 1925 joules while climbing
Answer:
Explanation:
Given
n=5
0.3 fraction recrystallize after 100 min
According to Avrami equation

where y=fraction Transformed
k=constant
t=time


Taking log both sides


At this Point we want to compute 



taking log both sides



Rate of Re crystallization at this temperature
