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grandymaker [24]

3 years ago

15

At a temperature of -33.0 degrees C, a sample of confined gas exerts a pressure of 53.3 kPa. If volume remains constant, at what

temperature will the pressure reach 133 kPa?

1 answer:

Rasek [7]3 years ago

4 0

Answer: 598.9K = 325.9°C

Explanation:

P1= 53.3kPa T1= -33+273=240K

P2=133kPa , T2= ?

Applying P1/T1 = P2/T2

Substitute and Simplify

53.3/240 = 133/T2

T2= 598.9K = 325.9°C

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Harman [31]

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3 years ago

Ar (g) is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.

nata0808 [166]

Answer:

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4 years ago

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erik [133]

This may help you

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sukhopar [10]

Gay-Lussac's law gives the relationship between pressure and temperature of a gas.
it states that for a fixed amount of gas of constant volume pressure is directly proportional to temperature.
P/T = k
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$\frac{P1}{T1} = \frac{P2}{T2}$
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
temperature should be in the kelvin scale,
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3 years ago