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3 years ago

Calcium reacts with hydrochloric acid,HCI, to make calcium chloride and hydrogen gas (H2).

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

1.)calcium+hydrochloric acid -->calcium chloride +hydrogen

2.)Ca + 2HCl -->CaCl2 + H2

3.)3.55g

Explanation:

1.) pretty self explanatory

2.)Ca + HCl -->CaCl2 + H2

then balance

Ca + 2HCl -->CaCl2 + H2 (+2 infront of Hcl)

3.) take calcium and calcium chloride

Ca + CaCl2

then you need the relative atomic mass of both

Ca=40

CaCl2=71 (40+(35.5x2))

Ca=40 40/40=1 1x2=2g

Then repeat that exact equation for calcium chloride

CaCl2=71 71/40=1.775 1.775x3=3.55g

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Answer:

The empirical formula is: Fe(CO)₅

Explanation:

According the global reaction:

Feₓ(CO)y + O₂ → Fe₂O₃ + CO₂

You should calculate Fe₂O₃ and CO₂ moles, thus:

0,799 Fe₂O₃ grams × $\frac{1 mole}{159.69 Fe2O3 g}$ = 5,00×10⁻³ Fe₂O₃ moles

2,200 CO₂ grams × $\frac{1 mole}{44,01 CO2 g}$ = 5,00×10⁻²CO₂ moles

The ratio between Fe₂O₃ moles and CO₂ moles is 1:10. Thus ratio between x and y must be 1:5 because Fe₂O₃ has 2 irons but CO₂ has just one carbon.

Assuming the formula is Fe₁(CO)₅ the molecular weight is 195,9 g/mol. Thus:

1,959 Fe(CO)₅ grams × $\frac{1 mole}{195,9 Fe(CO)5 g}$ = 1,00×10⁻² Fe(CO)₅ moles

Thus, assuming 1,00×10⁻² moles as basis for calculation, the global reaction is:

1 Fe(CO)₅ + ¹³/₂O₂ → ¹/₂ Fe₂O₃ + 5 CO₂

With this balanced equation the moles produced have sense, thus, the empirical formula is: Fe(CO)₅

I hope it helps!

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3 years ago

1N2 + 3H2 -->

Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

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2 years ago

Acetonitrile (CH3CN) is an important industrial chemical. Among other things, it is used to make plastic moldings, which have mu

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Answer:

One carbon atom and the nitrogen atom have nonzero formal charges.

Explanation:

The compound Acetonitrile has sixteen valence electrons as is easily San from its structure. It contains a carbon nitrogen triple bond with a lone pair of electrons on nitrogen. All atoms satisfy the octet rule and there is no hyper valent atom in the molecule.

The formal charge an carbon and nitrogen is calculated as follows;

No. of valence electron on atom - [non bonded electrons + no. of bonds]

Therefore, for carbon and nitrogen, we have;

formal charge on carbon = 4 - (0 + 4) = 0

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Hence carbon and nitrogen both possess zero formal charges.

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3 years ago

What is the daughter nucleus (nuclide) produced when 227th undergoes alpha decay?

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Answer: -

²²³Ra is the daughter nuclide produced when ²²⁷Th undergoes alpha decay

Explanation: -

When alpha decay occurs, the mass number of the parent decreases by 4 and the atomic number decreases by 2.

Mass number of ²²⁷Th =227

Atomic number of ²²⁷Th = 90

Mass number of daughter = 227 - 4 = 223

Atomic number of daughter = 90 - 2 = 88

88 is the atomic number of Ra Radium.

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3 years ago