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3 years ago

Can you put this in order from least to greatest for me {335 B.C. 430 B.C. 400 B.C.}

Chemistry

2 answers:

AlekseyPX3 years ago

8 0

It would be 430 B.C. 400 B.C. 335 B.C.
I hope this helps ;)

notka56 [123]3 years ago

8 0

First it's 335 B.C. , next it's 400 B.C. , then lastly it's 430 B.C.

The same way you put this in order from "least to greatest" ... It's just like Mathematics terms of "least to greatest" .. Just with 'B.C.' added to it

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3 years ago

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How many moles of lithium are in 83 grams of lithium?

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onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency

mestny [16]

Answer : The excess reactant is, $H_2O$

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of $CaCN_2$ = 105.0 g

Mass of $H_2O$ = 78.0 g

Molar mass of $CaCN_2$ = 80.11 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $CaCO_3$ = 100.09 g/mole

First we have to calculate the moles of $CaCN_2$ and $H_2O$ .

$\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles$

$\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $CaCN_2$ react with 3 mole of $H_2O$

So, 1.31 moles of $CaCN_2$ react with $1.31\times 3=3.93$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $CaCN_2$ is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

$\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)$

$\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g$

Thus, the leftover amount of excess reagent is, 7.2 grams.

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3 years ago

which of the following would a chemist be most likely to study? a. a leaf floating on water c. a leaf being blown by the wind b.

Salsk061 [2.6K]

I think the correct answer from the choices listed above is option B. It would be a leaf changing color in autumn <span>would a chemist be most likely to study. A chemist should be more interested in processes that chemical reactions are most likely to occur and changes in color can be one of the indications of such reactions.</span>

6 0

3 years ago

The heat of solution of KI is 20.3 kJ/mol.

sesenic [268]

Since the heat of solution of KI is 20.3 kJ/mol, the answer to the question is a. Exothermic, ΔH is positive

There are two types of chemical reactions namely exothermic and endothermic reaction.

For exothermic reactions, heat is released. So, ΔH is positive

For endothermic reactions, heat is absorbed. So, ΔH is negative

Given the heat of solution of KI as 20.3 kJ/mol.

Since it is positive, the reaction is exothermic and ΔH is positive

Since the heat of solution of KI is 20.3 kJ/mol, the answer to the question is a. Exothermic, ΔH is positive

Learn more about heat of solution here:

brainly.com/question/15103902

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2 years ago