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steposvetlana [31]
3 years ago
12

The densities of crystalline co2 and nh3 at 160 k are 1.56 and 0.84 g/cm3, respectively. calculate their molar volumes.

Chemistry
2 answers:
lions [1.4K]3 years ago
8 0

<u>Answer:</u> The molar volume of carbon dioxide is 28.21cm^3 and that of ammonia is 20.275cm^3

<u>Explanation:</u>

To calculate the molar volume for the given densities, we use the mass to be molar mass.

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}      ......(1)

  • <u>For carbon dioxide:</u>

Density of carbon dioxide = 1.56g/cm^3

Molar mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

1.56g/cm^3=\frac{44.01g}{\text{Volume of carbon dioxide}}\\\\\text{Volume of carbon dioxide}=28.21cm^3

Hence, the molar volume of carbon dioxide is 28.21cm^3

  • <u>For ammonia:</u>

Density of ammonia = 0.84g/cm^3

Molar mass of ammonia = 17.031 g

Putting values in equation 1, we get:

0.84g/cm^3=\frac{17.031g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=20.275cm^3

Hence, the molar volume of ammonia is 20.275cm^3

Neporo4naja [7]3 years ago
7 0
The molar volume, symbol Vm<span>, is the </span>volume occupied by one mole of a substance at a given temperature and pressure. <span>It is equal to the </span>molar<span> mass divided by the mass density. Therefore, we calculate as follows:

Vm(CO2) = 44.01 / 1.56 = 28.21 cm^3 / mol
</span>Vm(NH3) = 17.03 / 0.84 = 20.27 cm^3 / mol
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The functions of the ears are:

I. Hearing by collecting and processing sound waves

II. Keeping our balance when we turn or bend over; option A

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The ear is one of the five sense organs in the body.

The sense organs are the organs which receive external stimulus and send it to the brain for processing and response.

The other sense organs are:

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1 year ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

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Answer:

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If you find this useful, please mark my answer as the brainliest.

Explanation:

If you find this useful, please mark my answer as the brainliest.

distilled water

Explanation:

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