1. Using the dilution equation;
M1V1=M2V2
M1 = 6.25 m, v1= 25.5 ml or 0.0255 liters
Therefore; (6.25 ×0.0255)= M (0.5)
M = 0.159375/0.5
Therefore Molarity is 0.31875 M Hcl
2. From the same equation
M1v1=m2v2
m1 = 0.02 m, v1=8.25 ml or 0.00825 l, while v2= 0.012 l
Thus, 0.02 ×0.00825 = M (0.012)
M = 0.000165/0.012
= 0.01375 m
Thus molarity is 0.01375 M KI
0005 * 0.002 = 5 * 0.002 = 0.010 = 10^-2
Answer:
5. the scattering of α particles by a metal foil
Explanation:
This is the classical Rutherford's experiment in which he bombarded a thin foil of gold with alpha particles which are positively charged helium nucleus.
He did observed that most of the particles passed through the foil relatively undeflected or if they were deflected it was by a very small angle.
Once in a while the alpha particle rebounded completely. An analogy is the one typically mentioned that it was as if we throw a ball at a piece of paper and it rebounds toward us.
This observations led Rutherford to conclude that the nucleus of the atom is very small positely charged and that the atom is relatively empty with electrons of very small masses. His model is referred as the Plum Pudding model and later Bohr modified it to the planetary model.
Answer:
It would sink because the density of the ball, 0.802 g/cm3, is greater than the density of gasoline.
Answer:
No
Explanation: There are 0.0001
