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2 years ago

Why do we call them "Neutralization reaction"?This is section 2.6 Chemical Reactions

1 answer:

7 0

Only some reactions are called neutralization reactions. The most common are acid-base reactions, and the reason is that the consequence of the reaction is the acidity of the acid is reduced, and the basicity of the base is reduced.

A canonical example would be HCl + NaOH = NaCl + H2O. The HCl solution is a very strong acid, e.g. it will react strongly with many things, including your skin if you get it on you. Same for the NaOH solution. However the result, for an equimolar reaction, would just be a solution of table salt (NaCl) in water, which has almost zero reactivity with anything. You can drink it. So we say in this reaction the acid and base have both been "neutralized" -- their potent powers eliminated... hope this helps!

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When the internal energy of a material increases,: a) its temperature will rise b) it will go through a phase change c) A and B

EastWind [94]

Answer:

a or b

Explanation:

5 0

2 years ago

Read 2 more answers

A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s accelerati

erica [24]

Final velocity(v) = 32 m/s
Initial velocity(u) = 10 m/s

Using kinematic equation v = u + at,

32 = 10 + a(3)

32-10
--------- = a
3

a = 22
----
3

a = 7.3 m/s^2.

Hence acceleration of the roller coaster is 7.3 m/s^2.

Hope this helps!!

8 0

3 years ago

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

Ludmilka [50]

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

$w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln} *100\%\\\\w/w\%=3.15\%$

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

4 0

2 years ago

How many of the zeros in the measurement 0.050060 are significant

Feliz [49]

I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore

6 0

2 years ago

Read 2 more answers

A sample of PCl5(g) was placed in an otherwise empty flask at an initial pressure of 0.500 atm and a temperature above 500 K. Ov

tia_tia [17]

Answer:

Kp = 0.81666

Explanation:

Pressure of PCl₅ = 0.500 atm

Considering the ICE table for the equilibrium as:

PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)

t = o 0.500

t = eq -x x x

--------------------------------------------- --------------------------

Moles at eq: 0.500-x x x

Given the pressure of PCl₅ at equilibrium = 0.150 atm

Thus, 0.500 - x = 0.150

x = 0.350 atm

The expression for the equilibrium constant is:

$K_p=\frac {P_{PCl_3}P_{[Cl_2}}{P_{PCl_5}}$

So,

$K_p=\frac{x^2}{0.500-x}$

x = 0.350 atm

Thus,

$K_p=\frac{{0.350}^2}{0.500-0.350}$

7 0

3 years ago