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Kay [80]
3 years ago
14

How is the polarity of water important for transpiration?.

Chemistry
1 answer:
garik1379 [7]3 years ago
6 0
Water molecules having ‘poles’ means they link together - this is important, because, as water evaporates from the stomata, water is pulled up the plant in a ‘transpiration stream’. This would not happen without the polarity of water.
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How many atoms are in a sample of 175 grams of sodium (Na)? The answer needs to be <br> a x 10^b
ValentinkaMS [17]
Atomic mass Sodium ( Na ) = 22.98 u.m.a

22.98 g ----------------- 6.02x10²³ atoms
175 g ------------------- ?? atoms

175 x ( 6.02x10²³) / 22.98 =

4.58x10²⁴ atoms of Na

hope this helps!

4 0
3 years ago
Do chemical equations with no reaction still have to be balanced
dangina [55]

Answer:

The same number of atoms of each element must appear on both sides of a chemical equation. However, simply writing down the chemical formulas of reactants and products does not always result in equal numbers of atoms. You have to balance the equation to make the number of atoms equal on each side of an equation.

Explanation:

5 0
3 years ago
Complete the transmutation equation below. Assume that there is only one unknown product. Np93239→Pu94239+?
aliya0001 [1]
I have attached the answer. hopefully, i read the problems correctly. let me know if I did not.

both problems are an example of beta decays. when an atoms' atomic number is increased by one. this is symbolized with -1 e

5 0
3 years ago
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
Can someone find from which website this test is?
Nadusha1986 [10]

Answer:

Try quizlet, they have everything on there

Explanation:

8 0
3 years ago
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