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2 years ago

Why is the sky blue??

Chemistry

1 answer:

borishaifa [10]2 years ago

6 0

Answer:

The gases and particles of earths atmosphere scatter sunlight in different directions making the sky a specific color. Since blue light travels shorter, smaller waves its scattered more than others.

You might be interested in

If 24.6 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 301 Kelvin and 1.01 atmosph

nikitadnepr [17]

Juancastillorc your answer to your problem is 37.

6 0

2 years ago

How many moles of TNT would be detonated if you used 539.88 grams of TNT? The structure of TNT is C7H5N3O6. Round your answer to

Kruka [31]

Answer:

Moles of TNT = 2.38 moles

Explanation:

First , calculate the molar mass of the compound TNT

The formula is : C7H5N3O6

How to calculate molar mass?

Molar mass : It is the mass of substance in grams which is present in 1 mole of the compound.It is calculated by:

Molar mass = Number of atoms x the atomic mass of the element

Atomic mass of the elements are given below :

C = 12.0107

H = 1.0079

N = 14.0067

O = 15.9994

Molar mass of C7H5N3O6 =

= (7 x C) + (5 x H) + (3 x N) + (6 x O)

= 7(12.0107) +5(1.0079) + 3(14.0067) + 6(15.9994)

Molar mass = 227 .13 gram/mole

Mole are calculated using the formula:

$Moles =\frac{given\ mass}{Molar\ mass}$

Given mass = 539.88 grams

Molar mass = 227.13 g/mole

$Moles =\frac{539.88}{227.13}$

= 2.3769

Moles = 2.38 moles

5 0

3 years ago

4HCl(g) + Si (s) ⇌ SiCl4 (l) + 2H2 (g) would be classified as a(n):

zheka24 [161]

Answer:

it will be classical as gas

3 0

2 years ago

A saturated solution of Pb(IO3)2 in pure water has a lead ion concentration of 5.0 x 10-5 Molar. What is the Ksp value of Pb(IO3

Orlov [11]

Answer:

Option (E) is correct

Explanation:

Solubility equilibrium of $Pb(IO_{3})_{2}$ is given as follows-

$Pb(IO_{3})_{2}\rightleftharpoons Pb^{2+}+2IO_{3}^{-}$

Hence, if solubility of $Pb(IO_{3})_{2}$ is S (M) then-

$[Pb^{2+}]=S(M)$ and $[IO_{3}^{-}]=2S(M)$

Where species under third bracket represent equilibrium concentrations

So, solubility product of $Pb(IO_{3})_{2}$ , $K_{sp}=[Pb^{2+}][IO_{3}^{-}]^{2}$

Here, $[Pb^{2+}]=S(M)=5.0\times 10^{-5}M$

So, $[IO_{3}^{-}]=2S(M)=(2\times 5.0\times 10^{-5})M=1.0\times 10^{-4}M$

So, $K_{sp}=(5.0\times 10^{-5})\times (1.0\times 10^{-4})^{2}=5.0\times 10^{-13}$

Hence option (E) is correct

7 0

2 years ago

The rate constant for a certain reaction is k = 4.70×10−3 s−1 . If the initial reactant concentration was 0.700 M, what will the

Lynna [10]

Answer:

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

Explanation:

The unit of k is s⁻¹.

The order of the reaction = first order.

First order reaction: A first order reaction is a reaction in which the rate of reaction depends only the value of the concentration of the reactant.

$-\frac{d[A]}{dt} =kt$

[A] = the concentration of the reactant at time t

k= rate constant

t= time

Here k= 4.70×10⁻³ s⁻¹

t= 4.00

[A₀] = initial concentration of reactant = 0.700 M

$-\frac{d[A]}{dt} =kt$

$\Rightarrow -\frac{d[A]}{[A]}=kdt$

Integrating both sides

$\Rightarrow\int -\frac{d[A]}{[A]}=\int kdt$

⇒ -ln[A] = kt +c

When t=0 , [A] =[A₀]

-ln[A₀] = k.0 + c

⇒c= -ln[A₀]

Therefore

-ln[A] = kt - ln[A₀]

Putting the value of k, [A₀] and t

- ln[A] =4.70×10⁻³×4 -ln (0.70)

⇒-ln[A]= 0.375

⇒[A] = 0.686

Therefore the concentration of the reactant after 4.00 minutes will be 0.686M.

5 0

3 years ago