Answer:
4.43 kW
Explanation:
Since Intensity I = P/A = E²/2cμ₀ where P = Power, A = Area = 4πr² where r = distance from source = 61 m and E = electric field amplitude = 8.45 V/m.
P = E²A/2cμ₀ = E²4πr²/2cμ₀ = 2πE²r²/cμ₀
= 2π(8.45 V/m)²(61 m)²/3 × 10⁸ m/s × 4π × 10⁻⁷ Tm/A
= 4428.1 W
= 4.4281 kW ≅ 4.43 kW
A medium is a substance or material that carries the wave. Sounds waves need a medium in order to travel through a wave to help it travel as it cannot travel through a vacuum. Mechanical waves need a medium to transport energy.
The pressure at the bottom of the tank is given by:
P = ρgh
P = pressure, ρ = fluid density, g = gravitational acceleration, h = depth
Given values:
ρ = 820kg/m³, g = 9.8m/s², h = 4.5m
Plug in and solve for P:
P = 820(9.8)(4.5)
P = 36000Pa
Energy at top = U = mgh = 40 * 9.8 * 12 = 4704 J
Energy at bottom = 1/2 mv² = 1/2 * 40 * 10² = 4000 / 2 = 2000 J
Energy Lost = Final - Initial = 4704 - 2000 = 2704 J
In short, Your Answer would be 2704 Joules
Hope this helps!
