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fiasKO [112]
3 years ago
14

Please help ASAP I have to turn this in soon

Physics
2 answers:
amid [387]3 years ago
7 0

Answer:

Almost every scientist has a theory about the things that they discover and if the things are un-explainable it is a scientific law.

The goverment has laws to keep people safe and important people have important theories if they are not there.

Explanation:

I hope this helps!

Allisa [31]3 years ago
5 0

Answer:

See in explanation

Explanation:

Scientific use: The Einstein's THEORY of relativity states that "Time Is Absolute".

Everyday use: Einstein's LAW of relativity says that time is not the same at all places and events.

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Derive Isothermal process through ideal gas.(anyone plzz!!)​
zysi [14]

Answer:

Hey, bro here is the explanation....

Explanation:

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8 0
3 years ago
You are part of the designing team for a new solar thermal power plant. The plant will use thermal energy storage to produce ele
Harman [31]

Explanation:

Below is an attachment containing the solution.

4 0
3 years ago
The wavelength of light that has a frequency of 1.20 × 1013 s-1 is ________ m.
klio [65]
The relationship between frequency and wavelength for an electromagnetic wave is
c=f \lambda
where
f is the frequency
\lambda is the wavelength
c=3 \cdot 10^8 m/s is the speed of light.

For the light in our problem, the frequency is f=1.20 \cdot 10^{13} s^{-1}, so its wavelength is (re-arranging the previous formula)
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{1.20 \cdot 10^{13} s^{-1}}=  2.5 \cdot 10^{-5}m
8 0
3 years ago
An air hockey game has a puck of mass 30 grams and a diameter of 100 mm. The air film under the puck is 0.1 mm thick. Calculate
OverLord2011 [107]

Answer:

time required after impact for a puck is 2.18 seconds

Explanation:

given data

mass = 30 g = 0.03 kg

diameter = 100 mm = 0.1 m

thick = 0.1 mm = 1 ×10^{-4} m

dynamic viscosity = 1.75 ×10^{-5} Ns/m²

air temperature = 15°C

to find out

time required after impact for a puck to lose 10%

solution

we know velocity varies here 0 to v

we consider here initial velocity = v

so final velocity = 0.9v

so change in velocity is du = v

and clearance dy = h

and shear stress acting on surface is here express as

= µ \frac{du}{dy}

so

= µ  \frac{v}{h}   ............1

put here value

= 1.75×10^{-5} × \frac{v}{10^{-4}}

= 0.175 v

and

area between air and puck is given by

Area = \frac{\pi }{4} d^{2}

area  =  \frac{\pi }{4} 0.1^{2}

area = 7.85 × \frac{v}{10^{-3}} m²

so

force on puck is express as

Force = × area

force = 0.175 v × 7.85 × 10^{-3}

force = 1.374 × 10^{-3} v    

and now apply newton second law

force = mass × acceleration

- force = mass \frac{dv}{dt}

- 1.374 × 10^{-3} v = 0.03 \frac{0.9v - v }{t}

t =  \frac{0.1 v * 0.03}{1.37*10^{-3} v}

time = 2.18

so time required after impact for a puck is 2.18 seconds

3 0
3 years ago
What are the differences between concave lens and concave mirrors?
Pavel [41]

Explanation:

A concave mirror can form real, inverted images of various sizes and virtual, erect and enlarged images whereas a concave lens forms only virtual, errect and diminished images.

8 0
3 years ago
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