9 Newtons on the right, because:
Right and left are opposite directions, however, in the same direction.
We know that, opposite directions, the signal is of subtraction. So, you need to make the difference between 22 and 13, you will see that it is 9. Therefore, the Resulting Force will be 9.
The answer is CH4, 2O2, ? CO2 H20.
In the reaction, the the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide. The little number written at the lower right after an atom (subscript) tells how many of that atom are in the molecule. The big number written in front of a molecule (coefficient) shows how many of that molecule there are. All the atoms in the products come from the atoms in the reactants.
The reactants are on the left side of the equation and the products are on the right. In the reaction, the bonds in the methane and oxygen come apart, the atoms rearrange and then re-bond to form water and carbon dioxide
All the atoms in the reactants form the products so the mass of the reactants and the products is the same. No new atoms are created and no atoms are destroyed.
To solve the problem you must first know that by keeping the linear moment P1 = P2. You must find P1 from the system and equal it to P2 of the system, from that equation you clear the final velocity 1. Which will result in V1f = 60.16 cm / s to the north.I attach the solution.
Answer:
1.11
Explanation:
The index of the medium can be calculated using below formula
V= c/ n ............eqn(1)
Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s
n= index of the medium
c= speed of light= 3 x 10^8 m/s
Substitute for the values in eqn(1)
2.7 x 10^8 = (3 x 10^8 m/s)/ n
Making " n" subject of the formula, we have
n= (3 x 10^8 )/(2.7 x 10^8)
n= 1.11
Hence, the index of the medium is 1.11
Answer:
5.565 V
Explanation:
Radius of coil of generator=r=0.14 m
Length of wire=l=10 m
Magnetic field,B=0.24 T
Angular speed,
We have to find the peak emf of the generator.
Peak(maximum) induced emf of generator=
Using the formula
