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Novosadov [1.4K]
3 years ago
15

After glycolysis occurs, the products may enter the Krebs cycle. Which major products result from these reactions?

Biology
2 answers:
ivolga24 [154]3 years ago
4 0

The third option from top is the answer. The major products that result from the Krebs cycle are NADH,  FADH and ATP in that order.

The Krebs cycle is the central metabolic pathway in all aerobic organisms. The cycle is a series of eight reactions that occur in the mitochondrion. These reactions take a two carbon molecule called acetate and completely oxidize it to carbon dioxide.

The Krebs cycle serves two main purposes namely:

1.To increase the cell's ATP producing potential by generating  reduced electron carriers such as NADH and reduced ubiquinone.

2. To provide the cell with a variety of metabolic precursors.

By the time the eight reactions in Krebs cycle are over, one ATP, one FADH and four NADH molecules will have been produced

Vesnalui [34]3 years ago
4 0

answer for the whole test


After glycolysis occurs the products may enter the krebs cycle which major products results from these reactions.

Answer)ATP, FADHS, And NADH

What is not produced during glycolysis?

Answer) FADH2

What is the corect description of lactic acid fermentation?

Answer) An anaerobic process that occurs in muscles

When in the presence of sugar yeast perform which process

An anaerobic process that has CO2 as a byproduct


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1. Answer: 900x

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total mag= ocular * object

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2.  Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

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object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV).  Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm


4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm


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The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

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