Answer:
atomic number 8 and atomic number 12
Explanation:
atomic number 8 and atomic number 12 , element with the atomic number 8 is oxygen, and the element with atomic number 12 is Magnesium
Magnesium has low ionization energy, hence higher tendency to loose its two outermost electrons to form positive ion.
Oxygen has high electron affinity, hence higher tendency to accept or gain electrons to form negative ion.
The electronegativity difference between the element with atomic number 8 and element with atomic number 12 is greater for the formation of ionic bond
Answer:
131.5177 grams
Explanation:
You divide by Avogadro's number to turn it into moles then multiply by molar mass.
Even though there is no followings, I will try to include in this answer all the possible answers. I am sure about two elements that bound to hemoglobin when hemoglobin is in the R-state :Fe+2 and O2. As you should know, <span> R-state of hemoglobin is a relaxed form that is also called</span> <span>oxyhemoglobin, so the O2 definitely must be mentioned in there.</span>
Answer:
- <em>You could expect 3.48 grams of C₂H₄N₂</em>
Explanation:
You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.
1. Word equation:
Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water
2. Balanced chemical equation:

3. Convert the mass of each reactant into number of moles:
<u>Formula:</u>
- Number of moles = mass in grams/molar mass
<u>2.11g NH₃</u>
- Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃
<u>14.9g CO₂</u>
- Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂
<u>1.75g CH₄</u>
- Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄
4. Theoretical mol ratio
From the balanced chemical equation, using the coefficientes:

5. Limiting reagent
The available amounts of the reactants are:
Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:
- 0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂
Since there are 0.339 moles available, this is in excess.
- 0.124molNH₃ × (3molCH₄/8molNH₃) = 0.0465mol CO₂
Since there are 0.109 moles available, this is in excess too.
Hence, the limiting reagent is NH₃.
6. Yield
Use the theoretical ratio:
- 0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂
Convert to grams:
- Mass = number of moles × molar mass
- 0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer