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3 years ago

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What property of the elements is considered

1 answer:

ASHA 777 [7]3 years ago

4 0

Answer:

electro negativity

type of elements

the number of energy levels

I hope this helps you. I did a lot of reasearch to find the answer. Please mark me Brainliest! Thank you.

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Boron has 5 protons. If another proton gets added to boron, what will happen?

Alla [95]

If another proton gets added to the molecule there will be an increase in the atomic number and atomic mass by 1 unit and a new species will form.

here boron is taken which has an atomic number of 5 and atomic mass of 11 so when we add a proton to it, it will change into carbon having atomic number as 6 and atomic mass as 12.

$_{5}^{11}\textrm{B}+_{1}^{1}\textrm{p}\rightarrow _{6}^{12}\textrm{C}$

The new species formed will be $_{6}^{12}\textrm{C}$ .

6 0

3 years ago

Read 2 more answers

A chemist adds 405.0mL of a 0.79M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate th

Sophie [7]

Answer:

320 mmol

Explanation:

405.0 mL * 1L/1000 mL = 0.4050 L

0.79 M = 0.79 mol/L

0.79 mol/L * 0.4050 L=0.32 mol

0.32 mol * 10^3 mmol/1 mol = 320 mmol

4 0

3 years ago

Chromium (III) oxide reacts with hydrogen sulfide gas to form chromium (III) sulfide and water. To produce 421 g of cr2s3, how m

maw [93]

Cr₂O₃ ( s ) + 3H₂S ( g ) → Cr₂S₃ ( s ) + 3H₂O ( l )

mol Cr₂S₃ = 421 : 200.19 g/mol = 2.103

mol Cr₂O₃ ≈ mol Cr₂S₃ = 2.103 ( equivalent coefficient)

mass Cr₂O₃ = 2.103 x 151.99 g/mol = 319.63 gr

6 0

1 year ago

2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea

Alex_Xolod [135]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M

<u>Explanation:</u>

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}$

Moles of HI = 0.550 moles

Volume of container = 2.00 L

$\text{Initial concentration of HI}=\frac{0.550}{2}=0.275M$

For the given chemical equation:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

<u>Initial:</u> 0.275

<u>At eqllm:</u> 0.275-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[H_2][I_2]}{[HI]^2}$

We are given:

$K_c=0.0156$

Putting values in above expression, we get:

$0.0156=\frac{x\times x}{(0.275-2x)^2}\\\\x=-0.0458,0.0275$

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.0275 M

Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M

4 0

3 years ago

Copper(II) sulfate pentahydrate, CuSO4 ·5 H2O, (molar mass 250 g/mol) can be dehydrated by repeated heating in a crucible. Which

prohojiy [21]

Answer:

The water lost is 36% of the total mass of the hydrate

Explanation:

<u>Step 1:</u> Data given

Molar mass of CuSO4*5H2O = 250 g/mol

Molar mass of CuSO4 = 160 g/mol

<u>Step 2:</u> Calculate mass of water lost

Mass of water lost = 250 - 160 = 90 grams

<u>Step 3:</u> Calculate % water

% water = (mass water / total mass of hydrate)*100 %

% water = (90 grams / 250 grams )*100% = 36 %

We can control this by the following equation

The hydrate has 5 moles of H2O

5*18. = 90 grams

(90/250)*100% = 36%

(160/250)*100% = 64 %

The water lost is 36% of the total mass of the hydrate

8 0

2 years ago