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Pavlova-9 [17]
3 years ago
14

What property of the elements is considered

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

electro negativity

type of elements

the number of energy levels

I hope this helps you.  I did a lot of reasearch to find the answer.  Please mark me Brainliest!  Thank you.

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Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or
Julli [10]

NaHS is an acidic salt.

NaHS is obtained by replacement of one acidic hydrogen of `H2S` by Na (on reaction with NaOH).

<h3>What do we know about NaHS?</h3>

The chemical compound with the formula NaSH is sodium hydrosulfide. This substance is created when hydrogen sulfide is partially neutralized with sodium hydroxide. In the industrial setting, sodium sulfide and NaSH are frequently employed for the same things. Solid NaSH has no color.

Solution of sodium hydrosulfide is a colorless to light-yellow liquid. corrosive to flesh and metals. It is employed in the production of colors and paper pulp.

To learn more about acidic salt:

brainly.com/question/7178280

#SPJ4

7 0
1 year ago
Tellurium is a silvery-white, brittle element. Its electrical conductivity varies, but I’m creases slightly with exposure to sun
Lina20 [59]
B) Tellurium is a metalloid. Metalloids in some classifications are also or alternatively called “semi-metals.”
5 0
3 years ago
Read 2 more answers
When heat is applied to water a 10 degrees Celsius, what does the energy transform into?
LUCKY_DIMON [66]

Answer:

Gas

Explanation:

This is kind of like the process of evaporating

5 0
3 years ago
VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu
SOVA2 [1]

Answer:

31.9 °C  

Explanation:

The formula for the heat q absorbed by an object is

q = mCΔT where ΔT = (T₂ - T₁)

Data:

q = 12.35 cal

m = 19.75 g

C = 0.125 cal°C⁻¹g⁻¹

T₂ = 37.0 °C

Calculations

(a) Calculate ΔT

q = mCΔT

12.35 cal = 19.25 g × 0.125 cal°C⁻¹g⁻¹ × ΔT

12.35 = 2.406ΔT °C⁻¹  

ΔT  = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

 

6 0
3 years ago
Is zn2+ a transition metal?​
4vir4ik [10]

Answer:

Yes.

Explanation:

Zn2+ is the zinc ion in aqueous solution.

Zinc is a transition metal.

These metals are in the middle of the periodic table and have similar properties.

7 0
3 years ago
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