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3 years ago

A train travels at 50 km in three hours in the 96 km in four hours what is its average speed?

Physics

1 answer:

Mariana [72]3 years ago

3 0

Answer:

≈20.9 km/hr

Explanation:

Average speed is the distance divided by time.

The train travels 50 km in 3 hours, then 96 km in 4 hours. So overall, the train travels 146 km in 7 hours. The average speed is:

146 km / 7 hr ≈ 20.9 km/hr

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A falling ball of mass 0.5 kg experiences a downward force due to gravity of mg (where g = 9.8 m/s2) and an upward force of air

schepotkina [342]

Applying Newton's Second Law of Motion, the acceleration of the ball is 16.8 $m/s^2$

Given the following data:

Mass = 0.5 kg

Acceleration due to gravity = 9.8 $m/s^2$

Upward force = 3.5 N.

To find ball's acceleration, we would apply Newton's Second Law of Motion:

First of all, we would determine the net force acting on the ball.

$Net \; force = Upward\;force + Downward\;force$

$Downward\;force = 0.5$ × $9.8$

Downward force = 4.9 N

$Net \; force = 3.5 + 4.9$

Net force = 8.4 N

Mathematically, Newton's Second Law of Motion is given by this formula;

$Acceleration = \frac{Net\;force}{Mass}\\\\Acceleration = \frac{8.4}{0.5}$

Acceleration = 16.8  $m/s^2$ 

Therefore, the acceleration of the ball is 16.8 $m/s^2$

Read more here: brainly.com/question/24029674

6 0

3 years ago

A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the

Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

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3 years ago