A train moves at a constant velocity of 50 km/h. how far will it move in 0.05 h?
1 answer:
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Answer:
A) K / K₀ = 4 b) v / v₀ = 4
Explanation:
A) For this exercise we can use the conservation of mechanical energy
in the problem it indicates that the displacement was doubled (x = 2xo)
starting point. At the position of maximum displacement
Em₀ = Ke = ½ k (2x₀)²
final point. In the equilibrium position
= K = ½ m v²
Em₀ = Em_{f}
½ k 4 x₀² = K
(½ K x₀²) = K₀
K = 4 K₀
K / K₀ = 4
B) the speed value
½ k 4 x₀² = ½ m v²
v = 4 (k / m) x₀
if we call
v₀ = k / m x₀
v = 4 v₀
v / v₀ = 4
Answer : The correct option is, (c)
Explanation :
First we have to calculate the energy or heat.
Formula used :
where,
E = energy (in joules)
V = voltage (in volt)
I = current (in ampere)
t = time (in seconds)
Now put all the given values in the above formula, we get:
Now we have to calculate the heat capacity of the calorimeter.
Formula used :
where,
C = heat capacity of the calorimeter
= initial temperature =
= final temperature =
Now put all the given values in this formula, we get:
Therefore, the heat capacity of the calorimeter is,