Answer:
I am pretty sure that the answer would be a peer reviewed article.
Explanation:
I saw this because, an encyclopedia, published scientific journal, and a lab journal used in the original experiment, are all reliable sources of information.
Answer:
V₀ₓ = 10.94 m/s
V₀y = 18.87 m/s
Explanation:
To find the launch velocity, we use 1st equation of motion.
Vf = Vi + at
where,
Vf = Final Velocity of Ball = Launch Speed = V₀ = ?
Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)
a = acceleration = 376 m/s²
t = time = 0.058 s
Therefore,
V₀ = 0 m/s + (376 m/s²)(0.058 s)
V₀ = 21.81 m/s
Now, for x-component:
V₀ₓ = V₀ Cos θ
where,
V₀ₓ = x-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀ₓ = (21.81 m/s)(Cos 59.9°)
<u>V₀ₓ = 10.94 m/s</u>
<u></u>
for y-component:
V₀ₓ = V₀ Sin θ
where,
V₀y = y-component of launch velocity = ?
θ = Angle with horizontal = 59.9⁰
V₀y = (21.81 m/s)(Sin 59.9°)
<u>V₀y = 18.87 m/s</u>
<u></u>
B. accelerates in the direction of the force. this is because the force is now unbalanced, causing the object to move in that direction. it's like pushing a pen off the table. you applied force in that direction and since the pen doesn't have enough inertia to withstand your unbalanced force, it rolls off the table.
The relationship between electrical and charge force is that electrical force strengthens and increases the energy pulses and reflects off an object and makes the force about two times greater with charge.
