Compound axial member ABC has a uniform diameter of d = 1.50 in. Segment (1) is an aluminum [E1 = 10,000 ksi] alloy rod with a l
ength of L1 = 90 in. Segment (2) is a copper [E2 = 17,000 ksi] alloy rod with a length of L2 = 130 in. When axial force P is applied, a strain gage attached to copper segment (2) measures a normal strain of 2 = 2,100 in./in. in the longitudinal direction. What is the total elongation of member ABC?
1 answer:
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The trains take <u>57.4 s</u> to pass each other.
Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.
therefore,
The relative velocity of the train A with respect to B is given by,
If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.
The trains are a distance d = 2.71 km apart.
Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,
Substitute 2.71 km for d and 170 km/h for
Express the time in seconds.
Thus, the trains cross each other in <u>57.4 s</u>.
Answer:
h = 3.1 cm
Explanation:
Given that,
The volume of a oil drop, V = 10 m
Radius, r = 10 m
We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :
So, the thickness of the film is equal to 3.1 cm.
Answer:
536,904 J/s
Explanation:
The energy output from motor is the input energy in the machine.
We know that efficiency is percentage energy ouput to energy input, and expressed as
Where n and E represent efficiency and energy respectively, subscripts o and i represent output and input respectively. Since for the machine we have the input energy then the output will be the product of efficiency and input energy
Energy output=0.6*1200 hp=720 hp
Converting hp to J/s we multiply by 745.7
Energy is 720*745.7=536,904 J/s