Non metals tend to have higher ionization energies
Answer:
The magnitude of the hiker’s displacement is 2.96 km
Explanation:
Let the initial displacement of the hiker, = x = 2km
the final displacement of the hiker, = y = 1.4 km
The resultant of the two vectors, According to Pythagorean theorem is the vector sum of the two vectors.
R' = x' + y'
Check the image uploaded for solution;
Answer:
kidney
Explanation:
thats where your pee goes through
Answer:
1.84 m
Explanation:
For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.
So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,
a = g + rω²
= 9.8 m/s² + 1.10 m × (18.85 rad/s)²
= 9.8 m/s² + 390.85 m/s²
= 400.65 m/s²
Now, using v² = u² + 2a(h₂ - h₁) where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.
v² = u² + 2a(h₂ - h₁)
So, v² - u² = 2a(h₂ - h₁)
h₂ - h₁ = (v² - u²)/2a
h₂ = h₁ + (v² - u²)/2a
substituting the values of the variables into the equation, we have
h₂ = 1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)
h₂ = 1.3 m + [-430.15 (m/s)²]/-801.3 m/s²
h₂ = 1.3 m + 0.54 m
h₂ = 1.84 m
The speed of the stopper is 4.95 m/s, while the centripetal force on the stopper and the tension in the string is 3.42N each.
The mass of the stopper is 0.13 Kg, the length of the string to which it is attached is 0.93 m. The stopper swung and made one revolution in 1.18 seconds, so the time period of revolution of the stopper is 1.18 seconds.
The relation between the time period and the angular speed is,
T = 2π/W
W is angular speed and T is the time period of revolution.
Putting values,
1.18 = 2π/W
W = 5.32 rad/s.
The speed of the stopper can be found as,
v = rW
r is the length of the string,
V = 4.95 m/s.
The centripetal force on the stopper is given by,
F = MV²/r
Putting values,
F = 0.13 x 4.95 x 4.95/0.93
F = 3.42 N.
The tension in the string will be equal to the centripetal force on the stopper, so, the tension is 3.
42 N.
To know more about centripetal force, visit,
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