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dsp73
3 years ago
14

Explain why liquid freshwater is considered a limited resource.

Chemistry
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

Freshwater is such a limited resource because there is such a little amount of freshwater found on Earth. About 77% of fresh water on Earth is frozen in glaciers and polar ice caps. Because of this, there is very little fresh water available for humans to use.

Explanation: Hope this helps.

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Try using Google Scholar. It'll show you tons of educational resources on topics you look up. Good luck with your report! Hope this helps!
7 0
3 years ago
What will happen if the concentration of water inside a cell is higher than the concentration of water outside a cell?
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If the concentration of water inside a cell is higher than the concentration of water outside a cell, osmosis will take place, as water will move from an area of low solute concentration inside the cell to higher solute concentration, outside the cell.
7 0
2 years ago
Iron and oxygen react together to make iron (III) oxide (rust). You know that this is a chemical reaction and not a nuclear reac
Alona [7]
The atoms didn't change we only added 2 different ones together. 2nd one is right
7 0
2 years ago
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How many atoms are in 1.15 mole Cu?
xxMikexx [17]
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Multiply everything on the top= 6.93 x 10^23
Divide by everything on the bottom = 6.93 x 10^23
Answer: 6.93 x 10^23 atoms Cu.

4 0
2 years ago
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The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
MAVERICK [17]

Answer:

Approximately 2.46\; \rm mol.

Explanation:

Make use of the molar mass data (M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}) to calculate the number of moles of molecules in that 64.0\; \rm g of \rm C_2H_2:

\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}.

Make sure that the equation for this reaction is balanced.

Coefficient of \rm C_2H_2 in this equation: 2.

Coefficient of \rm H_2O in this equation: 2.

In other words, for every two moles of \rm C_2H_2 that this reaction consumes, two moles of \rm H_2O would be produced.

Equivalently, for every mole of \rm C_2H_2 that this reaction consumes, one mole of \rm H_2O would be produced.

Hence the ratio: \displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1.

Apply this ratio to find the number of moles of \rm H_2O that this reaction would have produced:

\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}.

3 0
3 years ago
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