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3 years ago

Harry Hess resurrected Wegener’s continental drift hypothesis and also the mantle convection idea of Holmes.

Chemistry

2 answers:

stepan [7]3 years ago

7 0

Answer:

true

Explanation:

aleksklad [387]3 years ago

3 0

He is right its True

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Which property of a mineral sample does not influence how quickly it settles in water? 1) density 2) hardness 3) shape 4) size

satela [25.4K]

<h3><u>Answer</u>;</h3>

4) size

<h3><u>Explanation</u>;</h3>

The mineral’s physical properties are used in identifying minerals and are determined by its chemical composition and crystal structure.
<u>Streak</u> is the color of the mineral in powdered form and since it is a more accurate illustration of the mineral’s color, its is a more reliable property of minerals than color for identification.
<u>Hardness</u> is one of the better properties of minerals to use for identifying a mineral. Hardness is a measure of the mineral’s resistance to scratching.
<u>Density</u> may be used to identify minerals. It is used to describe the amount of matter in a certain amount of space. Substances that have more matter packed into a given space have higher densities.

8 0

3 years ago

Consider this reaction: h2s hno3 right arrow. s no h2o reduction half-reaction: n 5 3e- right arrow. n 2 oxidation half-reaction

Vera_Pavlovna [14]

The coefficients of H2S and HNO3 in the balanced reaction equation are 2 and 3 respectively.

<h3>Chemical reaction</h3>

In a chemical reaction, reactans interact in a unique way to form products. In this case, the unbalanced reaction equation is; H2S + HNO3-----> NO + H2O.

Since this reaction is redox and electrons are lost/gained in the process, the coefficients of H2S and HNO3 in the balanced reaction equation are 2 and 3 respectively.

Learn more about chemical reactions: brainly.com/question/22817140

#SPJ4

7 0

2 years ago

2Na3N3 -> 2Na + 3N2<br><br> if 0.58 mol if NaN3 reacts, what mass of nitrogen would result

Ronch [10]

Answer:

Mass = 24.36 g of N₂

Explanation:

The balance chemical equation for the decomposition of NaNO₃ is as follow;

2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

2 moles of NaNO₃ produces = 3 moles of N₂

So,

0.58 moles of NaNO₃ will produce = X moles of N₂

Solving for X,

X = 3 mol × 0.58 mol / 2 mol

X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

8 0

3 years ago

Identify the number and kinds of atoms present in a molecule of each compound butane

ohaa [14]

The butane is a kind of alkane. And there is only carbon and hydrogen and single bonds. The formula of butane is C4H10. There are four carbon atoms and ten hydrogen atoms present in one butane molecule.

4 0

3 years ago

Consider the reaction

SOVA2 [1]

Answer :

(a) The average rate will be:

$\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s$

(b) The average rate will be:

$\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)$

The expression for rate of reaction :

$\text{Rate of disappearance of }Br^-=-\frac{1}{5}\frac{d[Br^-]}{dt}$

$\text{Rate of disappearance of }BrO_3^-=-\frac{d[BrO_3^-]}{dt}$

$\text{Rate of disappearance of }H^+=-\frac{1}{6}\frac{d[H^+]}{dt}$

$\text{Rate of formation of }Br_2=+\frac{1}{3}\frac{d[Br_2]}{dt}$

$\text{Rate of formation of }H_2O=+\frac{1}{3}\frac{d[H_2O]}{dt}$

Thus, the rate of reaction will be:

$\text{Rate of reaction}=-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{d[BrO_3^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}=+\frac{1}{3}\frac{d[H_2O]}{dt}$