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horsena [70]
3 years ago
7

What is the name of the first satellite sent into space

Physics
1 answer:
irina1246 [14]3 years ago
6 0

On October 4, 1957, Soviet satellite Sputnik, the world's first artificial satellite, blast into space and transmitted information via radio signals to Soviet scientists for three weeks. Sputnik II was launched in November 1957 with a a dog called Laika aboard.

I think hope you find this helpful.

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A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
marin [14]

Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

Mass m=5.97 * 10^{24} kg

Radius r=6.38 *10^6 m.

Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

V=3354.83m/s

Therefore

Period T is Given as

T=\frac{2 \pi *a}{V}

T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}

T=66262.4s

4 0
3 years ago
Sarah observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered if changes in
MAXImum [283]
This is the answer: Fossil's found in Susan's yard are from prehistoric times.
6 0
3 years ago
A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field
Sophie [7]

Explanation:

direction of electric field is same as that of force experienced by the test charge

8 0
2 years ago
A +2e charge is at the point (-1,0) mm in the x,y plane. A –e charge is at the point (0,1) mm. What is the electric field at the
Gennadij [26K]

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 

 Goodluck

Explanation:

4 0
2 years ago
Consider the three dip1acement vectors A = (3i - 3j) m, B = (i-4j) m, and C = (-2i + 5j) m. Use the component method to determin
tia_tia [17]

Answer with Explanation:

We are given that

A=3i-3j m

B=i-4 j m

C=-2i+5j m

a.D=A+B+C

D=3i-3j+i-4j-2i+5j

D=2i-2j

Compare with the vector r=xi+yj

We get x=2 and y=-2

Magnitude=\mid D\mid=\sqrt{x^2+y^2}=\sqrt{(2)^2+(-2)^2}=2\sqrt 2 units

By using the formula \mid r\mid=\sqrt{x^2+y^2}

Direction:\theta=tan^{-1}\frac{y}{x}

By using the formula

Direction of D:\theta=tan^{-1}(\frac{-2}{2})=tan^{-1}(-1)=tan^{-1}(-tan45^{\circ})=-45^{\circ}

b.E=-A-B+C

E=-3i+3j-i+4j-2i+5j

E=-6i+12j

\mid E\mid=\sqrt{(-6)^2+(12)^2}=13.4units

Direction of E=\theta=tan^{-1}(\frac{12}{-6}=tan^{-1}(-2)=-63.4^{\circ}

4 0
3 years ago
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