Answer:
Explanation:
Step 1. Determine the cell potential
<u> E°/V </u>
2×[Cr ⟶ Cr³⁺ + 3e⁻] 0.744 V
<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu] </u> <u>0.3419 V
</u>
2Cr + 3Cu²⁺ ⟶ 3Cu + 2Cr³⁺ 1.086 V
Step 2. Calculate ΔG°
Here's the numbers
H = +1
Cl = -1
Answer: The mass of given amount of copper (II) cyanide is 462.4 g
Explanation:
To calculate the number of moles, we use the equation:
We are given:
Moles of copper (II) cyanide = 4 moles
Molar mass of copper (II) cyanide = 115.6 g/mol
Putting values in above equation, we get:
Hence, the mass of given amount of copper (II) cyanide is 462.4 g
Answer:
6.9428 kg of CO2
Explanation:
1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.
9.5 x 10^25 CO2 molecules
= 157.75 moles CO2
2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.
= 6942.79g
3) Convert 6942.79 grams into kilograms (divide by 1000):
6.9428 kg
Answer:
a. HCl + NH₃ ⇄ NH₄Cl
b. KOH + NH₄⁺ ⇄ K⁺ + NH₃ + H₂O
Explanation:
A buffer system is made by a weak base (ammonia, NH₃) and its conjugate acid (ammonium ion NH₄⁺ coming from ammonium chloride NH₄Cl). Its function is to resist abrupt changes in the pH when acids or bases are added.
a. When aqueous hydrochloric acid is added, it reacts with the base of the buffer. The corresponding equation is:
HCl + NH₃ ⇄ NH₄Cl
b. When aqueous potassium hydroxide is added, it reacts with the acid of the buffer. The corresponding equation is:
KOH + NH₄⁺ ⇄ K⁺ + NH₃ + H₂O
