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shepuryov [24]
4 years ago
14

Fine the solution set 6x^2+x-1=0 separate the two values with a comma

Mathematics
1 answer:
Ksenya-84 [330]4 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Given

6x² + x - 1 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 6 × - 1 = - 6 and sum = + 1

The factors are + 3 and - 2

Use these factors to split the x- term

6x² + 3x - 2x - 1 = 0 ( factor the first/second and third/fourth terms )

3x(2x + 1) - 1(2x + 1) = 0 ← factor out (2x + 1) from each term

(2x + 1)(3x - 1) = 0

Equate each factor to zero and solve for x

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - \frac{1}{2}

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = \frac{1}{3}

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