Answer:
WX = WY
9x - 11 = 7x - 3..........Then subtract 7x to the other side such that
2x - 11 = -3..........Then add 11 to both sides such that
2x = 8...........Then divide 2 such that
x = 4
Now we can find each side such that
WX = 9(4)-11 = 25
WY = 7(4)-3 = 25
XY = 4(4)+1 = 17
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➷ First identify and assign the variables:
q = number of quarters
d = number of dimes
This is what we know:
q + d = 22
A quarter is 25 cents and a dime is 10 cents
You can write this as:
0.25q + 0.1d = 3.40
Rearrange the first equation for d
d = 22 - q
Substitute this value into the other equation:
0.25q + 0.1(22 - q) = 3.40
Simplify:
0.25q + 2.2 - 0.1q = 3.40
0.15q + 2.2 = 3.4
Subtract 2.2 from both sides:
0.15q = 1.2
Divide both sides by 0.15:
q = 8
Substitute into the first equation:
8 + d = 22
d = 14
Therefore, there are 8 quarters and 14 dimes.
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➶ Hope This Helps You!
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Maybe 6+4x??? Not sure though
5,280/40=132.
Jackrabbits can go up to 132 feet per seconds.
Hope this helps!
Answer:
a = 1
b = 3
c = 1
d = 2
e = 6
f = 8
Step-by-step explanation:
Any integer with power as zero = 1
<h3>
For a</h3>
2^x
2^0
= 1
<h3>
For b</h3>
3 * 2^x
3 * 2^0
3 * 1
= 3
<h3>
For c</h3>
2 ^ 3(x)
2 ^ 3(0)
2 ^ 0
= 1
<h3>For d</h3>
2^1
= 2
<h3>
For e</h3>
3 * 2^x
3 * 2^1
3 * 2
= 6
<h3>For f</h3>
2 ^ 3(x)
2 ^ 3(1)
2 ^ 3
2 * 2 * 2
= 8