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Elina [12.6K]
3 years ago
10

Where can you buy lithium

Chemistry
2 answers:
ss7ja [257]3 years ago
7 0
On the website. just type in your own question!!!
Ivenika [448]3 years ago
5 0
You can get it on google on Herbs Direct.
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Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?
irina [24]
Formula: molality, m = n solute / kg solvent

n solute = # of moles of solute = mass(g) / molar mass

Molar mass of Mg Br2 = 184.11 g/mol

m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg
3 0
3 years ago
What does a Mitochondrion do
Slav-nsk [51]

Answer:

Explanation:

Power house of the cell.

It carries the DNA strand from the ribosome

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3 years ago
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How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride.<br> (LiF)?
dsp73

Answer:

V = 3.1 L      

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L         (M = mol/L)

4 0
3 years ago
The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the
Alla [95]

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

8 0
3 years ago
The most likely van't Hoff factor for an 0.01 m calcium iodide solution is
monitta

This problem is providing us with the molality of a solution of calcium iodide as 0.01 m. So the most likely van't Hoff factor is required and theoretically found to be 3 due to the following:

<h3>Van't Hoff factor:</h3>

In chemistry, the correct characterization of solutions also imply the identification of the ions it will release in aqueous solution. For that reason, the van't Hoff factor gives us an idea of this number, according to the formula the solute has got.

In such a way, for calcium iodide, we write its ionization equation as shown below:

CaI_2\rightarrow Ca^{2+}+2I^-

Assuming it is able to ionize due to the low molality, because if it was higher, then it won't ionize. Hence, since we have three moles of ion products, one Ca²⁺ and two I⁻, we can conclude the van't Hoff factor would be 3, although calculations may lead to a different, yet close result.

Learn more about the van't Hoff factor: brainly.com/question/23764376

5 0
3 years ago
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