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3 years ago

What are the characteristics of Mercury? (Select all that apply.)

Chemistry

2 answers:

netineya [11]3 years ago

6 0

Answer:

Mercury has less gravity than the earth, mercury is the closest planet to the sun. I hope this helps.

Explanation:

Sunny_sXe [5.5K]3 years ago

5 0

Answer:

less gravity, closest to the sun

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Is mixing butter, granulated sugar, and brown sugar until it's creamy a physical or chemical change and why

Nadusha1986 [10]

Answer:

Physical

Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.

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2 years ago

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lora16 [44]

Find the molar mass of CH3 and divide that by 45.0. That should give a whole number and then mult that whole number by CH3 to find molecular formula to get like ( incorrect ex: C2H6) which is mult by 2

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2 years ago

Warm water rising to the surface of the

White raven [17]

Answer:

convection

Explanation:

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2 years ago

According to Dalton, atoms cannot be SELECT ALL THAT APPLY a Created b Destroyed c Subdivided d Bonded

Sveta_85 [38]

Answer:

The answer is subdivided,created or destroyed

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2 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

4 0

1 year ago