What mass of water will change its temperature by 20.0 degrees Celsius when 515 J of heat is added to it? the specific heat of w
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Answer:
0.03605 V/m is the electric field in the gold wire.
Explanation:
Resistivity of the gold =
Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)
Diameter of the wire = d = 0.9 mm
Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm =
( 1mm = 0.001 m)
Area of the cross-section =
Resistance of the wire = R
Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)
( Ohm's law)
We know, Electric field is given by :
0.03605 V/m is the electric field in the gold wire.