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AfilCa [17]
3 years ago
10

What mass of water will change its temperature by 20.0 degrees Celsius when 515 J of heat is added to it? the specific heat of w

ater is 4.18J/g*C.
Physics
1 answer:
andrey2020 [161]3 years ago
4 0
The problem can be solve using the formula:
q = m Cp T
where q is the heat added to the substance
m is the mass of the substance
Cp is the specific of the substance
T is the change in temperature of the subtance

q = m Cp T
515 = m ( 4.18 ) ( 20)
m = 515 / ( 4.18) ( 20 )
m = 6.16 g of water

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Explanation:

Speed is distance over time.

500 km / 2 hr = 250 km/hr

Velocity is speed and direction.

250 km/hr north

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A Block slides down an incline that makes an angle of 30? with the horizontal direction. The coefficient of kinetic friction bet
astraxan [27]

Answer:

Acceleration = 2.35 m/s^{2}

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

The two forces acting on block are weight and friction.

weight along the incline = mg cos60° = \frac{mg}{2} = 0.5 mg

Friction along incline = umg cos30° = mg 0.3\times \frac{\sqrt{3}}{2}

Friction along incline  = 0.26 mg

Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = \frac{net force}{mass} = 0.24 g = 2.35 m/s^{2}

The height of incline = 8 m

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v^{2}=u^{2}+2as

v^{2}= 2\times 0.24 \times 9.8\times 16

v= 8.67 m/s

5 0
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What is another name for the introitus? psych 230?
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Vaginal opening. areola is the part of the breast.
7 0
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On a winter day with a temperature of -10°C, 500g of snow (water ice) is brought inside where the temperature is 18 °C. The snow
Serjik [45]

Answer:

Explanation:

Mass of ice m = 500g = .5 kg

Heat required to raise the temperature of ice by 10 degree

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= .5 x 2093 x 10 J

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Heat required to melt the ice

= mass of ice x latent heat

0.5 x 334 x 10³ J

167000 J

Heat required to raise its temperature to 18 degree

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7 0
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A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

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Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
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