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AfilCa [17]
3 years ago
10

What mass of water will change its temperature by 20.0 degrees Celsius when 515 J of heat is added to it? the specific heat of w

ater is 4.18J/g*C.
Physics
1 answer:
andrey2020 [161]3 years ago
4 0
The problem can be solve using the formula:
q = m Cp T
where q is the heat added to the substance
m is the mass of the substance
Cp is the specific of the substance
T is the change in temperature of the subtance

q = m Cp T
515 = m ( 4.18 ) ( 20)
m = 515 / ( 4.18) ( 20 )
m = 6.16 g of water

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Fynjy0 [20]

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

6 0
3 years ago
g 2. In a laboratory experiment on standing waves a string 3.0 ft long is attached to the prong of an electrically driven tuning
abruzzese [7]

Answer:

The tension in string will be "3.62 N".

Explanation:

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or,

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frequency,

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= 0.096 lb

or,

= 0.0435 kgm/s²

Now,

The mass will be:

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= 0.0044 \ kg

As we know,

⇒  \lambda=\frac{2L}{n}

On substituting the values, we get

⇒     =\frac{2\times 0.9144}{4}

⇒     =0.4572 \ m

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⇒      =27.432 \ m/s

Now,

⇒  v=\sqrt{\frac{T}{\mu} }

or,

⇒  T=\frac{m}{l}\times v^2

On putting the above given values, we get

⇒      =\frac{0.0044}{0.9144}\times (27.432)^2

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7 0
3 years ago
You have a gold nugget and find its mass to be 25 grams. How much volume does this gold nugget occupy?
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According to the solving, the volume that this gold nugget occupies is 1.29 cm³.

<h3>What is volume?</h3>

Volume is a standard measure of three-dimensional space that is occupied. It is typically mathematically represented using standard or SI-derived units. Volume and the concept of length are connected. It is sometimes referred to as the object's capacity.

d= m/ V

m=  dV

V= m/d

<h3>So according to the given data,</h3>

The mass of the gold nugget is 25 grams.

The density of gold is 19.32 g/cm³.

We know that,

m= Vd

To find out the Volume(V),

V= m/d

V= (25 g)/(19.32 g/cm³)

V= 1.29 cm³.

According to the solving, the volume this gold nugget occupies is 1.29cm³.

To know more about questions of volume visit,

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