Answer:
h = 9.57 seconds
Explanation:
It is given that,
Initial speed of Kalea, u = 13.7 m/s
At maximum height, v = 0
Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :




t = 1.39 s
Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

Here, a = -g


h = 9.57 meters
So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.
As an egg falls towards the floor, it begins to travel faster and faster. When it slams into the floor, the egg is stopped almost immediately. This force of the floor against the eggshell is too large, so it breaks.
Answer:
30643 J
Explanation:
= Vacuum permeability = 
t = Time taken = 1 ns
c = Speed of light = 
= Maximum electric field strength = 
A = Area = 
Magnitude of magnetic field is given by

Intensity is given by

Power, intensity and time have the relation

The energy it delivers is 30643 J
Answer:
35.20 m
Explanation:
By the law of conservation of energy we have,



where m= mass of the skier, h= 3.00 m
D= horizontal distance=13.9 m
H= maximum height attained
Also, the horizontal distance covered by the skier is
D=vt


thus, height H in terms of D is given by


H=35.20 m