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Lemur [1.5K]
3 years ago
7

1.- Al aplicar una fuerza de 60 Newtons sobre un cuerpo, se produce una aceleración de 4 m/s2 calcula el valor de su masa.

Physics
1 answer:
patriot [66]3 years ago
4 0

Answer:

answer is D good luck on the rest

Explanation:

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A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t
Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

We can find the new volume by using the Ideal Gas Law:

PV = nRT

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature  

Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

nR = \frac{P_{1}V_{1}}{T_{1}}   (1)  

And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:

nR = \frac{P_{2}V_{2}}{T_{2}}   (2)

By equating (1) with (2):

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}                

V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.                                                

I hope it helps you!                  

3 0
3 years ago
A ball has a mass of 2g and a velocity of 3m/s. What is the ball's Kinetic Energy?​
NeTakaya

Answer: im not sire

Explanation: very sorry im not sure

7 0
3 years ago
Consider the three dip1acement vectors A = (3i - 3j) m, B = (i-4j) m, and C = (-2i + 5j) m. Use the component method to determin
tia_tia [17]

Answer with Explanation:

We are given that

A=3i-3j m

B=i-4 j m

C=-2i+5j m

a.D=A+B+C

D=3i-3j+i-4j-2i+5j

D=2i-2j

Compare with the vector r=xi+yj

We get x=2 and y=-2

Magnitude=\mid D\mid=\sqrt{x^2+y^2}=\sqrt{(2)^2+(-2)^2}=2\sqrt 2 units

By using the formula \mid r\mid=\sqrt{x^2+y^2}

Direction:\theta=tan^{-1}\frac{y}{x}

By using the formula

Direction of D:\theta=tan^{-1}(\frac{-2}{2})=tan^{-1}(-1)=tan^{-1}(-tan45^{\circ})=-45^{\circ}

b.E=-A-B+C

E=-3i+3j-i+4j-2i+5j

E=-6i+12j

\mid E\mid=\sqrt{(-6)^2+(12)^2}=13.4units

Direction of E=\theta=tan^{-1}(\frac{12}{-6}=tan^{-1}(-2)=-63.4^{\circ}

4 0
4 years ago
How high would you have to lift your 0.54kg textbook to give it 177 J of gravitational potential energy
kupik [55]
L 92993929193930 is the answer
5 0
3 years ago
Math the following to definitions
Leona [35]
Hi,
The answer should be:
Vector 5
Magnatude 4
Weight 1
Mass 2
Net force 6
Force 3

Hope this helps!
6 0
3 years ago
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