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Slav-nsk [51]
3 years ago
13

A heat pump is used to warm a building in the winter. This system implements an ideal vapor-compression cycle with R-134a as the

working fluid. The cycle operates between 200 kPa and 800 kPa, with a mass flow rate of 0.02 kg/s. Determine: (a) the heating load that can be met kW (b) the power input required for this system kW (c) the coefficient of performance (d) the warmest outside temperature at which this particular cycle is unable to operate ∘C
Engineering
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

See attachment for detailed answer.

Explanation:

Download pdf
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nadya68 [22]

Any collection of data or information that has been properly structured for quick search and retrieval by a computer is referred to as a database, often known as an electronic database.

<h3>What is electronic database?</h3>
  • Databases are designed to make it easy to save, retrieve, edit, and delete data while carrying out various data-processing tasks. In response to queries, a database management system (DBMS) retrieves data from the database.
  • Databases are briefly discussed after that. See computer science: Information systems and databases; information processing for a comprehensive explanation.
  • A file or collection of files used to store a database.
  • These files' contents can be divided up into records, each of which has one or more fields.
  • The fundamental units of data storage are fields, and each field typically contains data related to one feature or attribute of the thing that the database is describing.
  • Additionally, records are arranged into tables that contain details on the connections between their various fields.
  • A database in the strict sense offers cross-referencing capabilities, despite the fact that the term "database" is used broadly to refer to any collection of information in computer files.
  • Users can quickly search, rearrange, organize, and choose the fields in numerous records to access or produce reports on certain data aggregates using keywords and a variety of sorting instructions.

To Learn more About database Refer To :

brainly.com/question/518894

#SPJ1

5 0
1 year ago
Before finishing and installing a shelved cabinet you just constructed, you need to check the
Greeley [361]

Answer:

Carpenter's square

Explanation:

The most common hand tool used to measure or set angles with its application extending to setting angles of roofs and rafters. Another name of a Carpenter's square is a framing square.

Other hand tools that are used to measure angles are;

  • The combination square that allows a user to set both 90°  and 45° angles
  • A Bevel that allows users to set any angle they like.
  • A Protractor that resembles a bevel but its marks are marked in an arc.
  • An electromagnetic angle finder which gives a reading according to the measure of the arms adjusted by the user.
7 0
3 years ago
I WILL GIVE BRAINLIEST IF ANSWER FAST What is the measurement on this Dial Caliper?
garik1379 [7]

Answer:

b i think i dont see any dial caliper

Explanation:

8 0
3 years ago
The error in the trapezoidal rule is proportional to h^2 True b. False
Lynna [10]

Answer:

b) False

Explanation:

in trapezoidal rule the error is proportional to h^3 and the order of accuracy is proportional to h^3 .

Trapezoidal rule is numerical integration method .Trapezoidal rule is used to find the area of curves.In trapezoidal rule we finds the approximate value of integration.But the real value of integration will not differ to much from the value which finds by using trapezoidal rule.

4 0
3 years ago
Problem 4.079 SI A rigid tank whose volume is 3 m3, initially containing air at 1 bar, 295 K, is connected by a valve to a large
salantis [7]

Answer:

Q_{cv} = -1007.86kJ

Explanation:

Our values are,

State 1

V=3m^3\\P_1=1bar\\T_1 = 295K

We know moreover for the tables A-15 that

u_1 = 210.49kJ/kg\\h_i = 295.17kJkg

State 2

P_2 =6bar\\T_2 = 296K\\T_f = 320K

For tables we know at T=320K

u_2 = 228.42kJ/kg

We need to use the ideal gas equation to estimate the mass, so

m_1 = \frac{p_1V}{RT_1}

m_1 = \frac{1bar*100kPa/1bar(3m^3)}{0.287kJ/kg.K(295k)}

m_1 = 3.54kg

Using now for the final mass:

m_2 = \frac{p_2V}{RT_2}

m_2 = \frac{1bar*100kPa/6bar(3m^3)}{0.287kJ/kg.K(320k)}

m_2 = 19.59kg

We only need to apply a energy balance equation:

Q_{cv}+m_ih_i = m_2u_2-m_1u_1

Q_{cv}=m_2u_2-m1_u_1-(m_2-m_1)h_i

Q_{cv} = (19.59)(228.42)-(3.54)(210.49)-(19.59-3.54)(295.17)

Q_{cv} = -1007.86kJ

The negative value indidicates heat ransfer from the system

7 0
3 years ago
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