If 200 amperes flow from the positive terminal of a battery and operate the starter motor, how many amperes will flow back to th
1 answer:
Answer:
Amperes WB =<em> </em>
Explanation:
Amperes will flow back to the negative terminal because both the positive terminal and negative terminal contain the equivalent amount of current that will flow and it works in the starter motor.
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Answer:
The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
Explanation:
Minimum required thickness is the thickness of a material without corrosion allowance for each component based on the appropriate design that consider pressure, mechanical and structural loading.
Given that:
radius (r) = 65 mm = 65 × 10⁻³ m
Factor of safety (N) = 3.5
Inside presssure () = 11 MPa
Outside pressure () = 1 MPa
Yield strength () = 1000 MPa
Therefore:
, Substituting values,
The minimum required thickness for a steel pressure vessel (t) is given by the equation:
. Substituting values
The minimum required thickness for a steel pressure vessel (t) is 2.275 mm
Answer:
as pull up network. the metteing point of pull down and pull up is the point where we take the output
note 1: if two n-mos are connected in series it gives logical AND and p-mos paralle gives logical-AND
note 2: if two n-mos are connected in parallel it gives logical OR and p-mos series gives logical-OR
note 3: output is always complement of what we implement
example Y= (AB)'
image attached
A) F = (ABC + D(A+B) )'
pulldown:
this can be realize by takeing three n-mos in series which gives ABC ,two n-mos are parallel which in series with another n-mos whic gives D(A+B), now connect ABC and D(A+B) in parallel
pull up
this can be realize by takeing three p-mos in parallel which gives ABC ,two p-mos are series which is in serires with
another p-mos whic gives D(A+B), now connect ABC and D(A+B) in series
the out put will be (ABC + D(A+B) )'
so we require total 6-mos and 6-pmos total 12mos transistors
B) F = AC + BD
pull down
this can be realize by takeing two n-mos in series which gives AB ,two n-mos are in series
which whic gives BD, now connect AC and BD in parallel
pull up
this can be realize by takeing two p-mos in parallel which gives Ac ,two p-mos are in parallel
which whic gives BD, now connect AC and BD in series
the output is (AC+BD)'
to avoid the complement we have to connect the output to c-mos inverter then we get AC+BD
so we require 5-nmos, 5-pmos total 10 mos transistors
