Answer:
Tire rotation is the least likely cause of tire wear. So, the option D is correct.
Explanation:
Step1
Under-inflation is the process of tire failure under low pressure. This contributes the wear on tire.
Step2
On breaking, kinetic energy changes to heat energy because of rubbing of tire. So, rubbing action increases the wear on the tire.
Step3
Acceleration on the vehicle increases the rubbing action as well as the wear and tear on the tire. So, acceleration is an also a major cause of tire wear.
Step4
Tire rotation has least amount of wear and tear due to no rubbing action. It has less amount surface contact with the surface in rotation.
Thus, tire rotation is the least likely cause of tire wear. So, the option D is correct.
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step and very detailed solution of the given problem
4-ways tell me if I’m wrong
Answer:
8 μC
Explanation:
By definition, current is the rate of change of charge, so we can write the following equation for current I:
I = ΔQ / Δt
As charge must be conserved, all the charge carried by the current must add to the charge on the plates of the capacitor, so we can finf this incremental charge as follows:
ΔQ = I* Δt (assuming that current remains constant during the charging process)
⇒ ΔQ = 3 A* 2 μsec = 3 coul/sec*2 μsec = 6 μC
As the initial charge must be conserved also, the magnitude of the net electric charge of the capacitor must be as follows:
Qnet = Q₀+ ΔQ = 2 μC + 6 μC = 8 μC
Answer:
Explanation:
Hello,
In this problem, the piston-cylinder assembly make us state the energy balance as:
Thus, we must now compute 
in terms of Cv as follows:
Now, since heat is given off, its sign is negative, thus, the work is computed as:
This work means that work was done over the system in order to allow the compression.
The suppositions were:
- The change in the internal energy is a function of the temperature.
- Air is an ideal gas.
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