II) Water flows with an average speed of 3.0 m/s through a section of a stream that is 30 m wide and 1.0 m deep. The water then
1 answer:
Answer:
The 15 m wide section of the stream is 3 m deep.
Explanation:
The Flow rate of the water remains constant throughout.
Flow rate = Velocity x depth x width
Flow rate = (3)(30)(1)
Now the depth,width and velocity of the flow stream has changed but the flow rate still remains same. So,
Assuming depth to be D,
90 = (2)(15)(D)
D = 3 m
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(a) -2451 N
We can start by calculating the acceleration of the car. We have:
is the initial velocity
v = 0 is the final velocity of the car
d = 125 m is the stopping distance
So we can use the following equation
To find the acceleration of the car, a:
Now we can use Newton's second Law:
F = ma
where m = 1100 kg to find the force exerted on the car in order to stop it; we find:
and the negative sign means the force is in the opposite direction to the motion of the car.
(b)
We can use again the equation
To find the acceleration of the car. This time we have
is the initial velocity
v = 0 is the final velocity of the car
d = 2.0 m is the stopping distance
Substituting and solving for a,
So now we can find the force exerted on the car by using again Newton's second law:
As we can see, the force is much stronger than the force exerted in part a).