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baherus [9]
3 years ago
9

A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?

Physics
1 answer:
Ainat [17]3 years ago
4 0

Answer:

V = 5.83 m/s

Explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{2\times 35+10\times 0}{2+10}\\\\V=5.83\ m/s

So, the velocity of the box after the collision is equal to 5.83 m/s.

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Answer: c) Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

Hey

On Earth, you can move or you can not move. if you are moving 50 mph that means relative to Earth (not the Andromeda galaxy). When you start moving (accelerating) you are now moving relative to Earth. when you start slowing down (decelerating [most scientists just say you have negative acceleration]) you are starting to match your velocity to Earth's velocity.

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3 years ago
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Answer and Explanation:

In optics, a CoC(Circle of Confusion) is defined the minimum cross section of a paraxial bundle of rays made by a lens which is sphero-cylindrical type and can be viewed as an optical spot, which do not converge perfectly at the focus  while a point source is being imaged due to spherical aberration.

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3 years ago
Your heart pumps blood at a pressure of 100 mmHg and flow speed of 60 cm/s. At your brain, the blood enters capillaries with suc
Savatey [412]

Answer:

1.28 m

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Since g is constant, then

\rho_b h_b= \rho_m h_m

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