I need help PLEASSEE
1 answer:
We know that perpendicular lines have slopes which are negative inverses of each other. This means that the slope of the line we are going to need to find is 3.
Now, we can use the point-slope formula to find the actual equation of the line we are trying to find. The point-slope formula is
, where 
and 
are the coordinates of a point on the line and m is the slope.
Thus, the equation of the line we are trying to find is:
(y - 7) = 3(x - 2)
y - 7 = 3x - 6
y = 3x + 1
However, this is not an answer choice. The answers given have the constant on the right side of the equation. Thus, we will make our answer have the constant on the right side:
y - 3x = 1
-3x + y = 1
3x - y = -1
This is an answer choice. B, or 3x - y = -1 is the correct answer.
Now, we can use the point-slope formula to find the actual equation of the line we are trying to find. The point-slope formula is
Thus, the equation of the line we are trying to find is:
(y - 7) = 3(x - 2)
y - 7 = 3x - 6
y = 3x + 1
However, this is not an answer choice. The answers given have the constant on the right side of the equation. Thus, we will make our answer have the constant on the right side:
y - 3x = 1
-3x + y = 1
3x - y = -1
This is an answer choice. B, or 3x - y = -1 is the correct answer.
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9514 1404 393
Answer:
- ∠QSR = 78°
- ∠SQR = 51°
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
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Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
