Question

|x-2| + |2x+1| ≥ 3 How to solve this inequality? HELP

Answer 1

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0\:\\ \:\mathrm{Decimal:}&\:x\le \:-0.66666\dots \quad \mathrm{or}\quad \:x\ge \:0\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{2}{3}]\cup \:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

$\left|x-2\right|+\left|2x+1\right|\ge \:3$

$x$

$x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:0\le \:x$

$x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0$