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Mrac [35]
3 years ago
15

|x-2| + |2x+1| ≥ 3 How to solve this inequality? HELP

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer: \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0\:\\ \:\mathrm{Decimal:}&\:x\le \:-0.66666\dots \quad \mathrm{or}\quad \:x\ge \:0\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{2}{3}]\cup \:[0,\:\infty \:)\end{bmatrix}

Step-by-step explanation:

\left|x-2\right|+\left|2x+1\right|\ge \:3

x

x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:0\le \:x

x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0

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