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Artyom0805 [142]
3 years ago
13

Identify the reaction type for each generic chemical equation. A + B → AB: AB → A + B: Hydrocarbon + O2 → CO2 + H2O: AB + CD →

AD + CB:
Physics
2 answers:
Ghella [55]3 years ago
6 0

Answer:

1. A+B\rightarrow AB: Synthesis

AB\rightarrow A+B: Decomposition

Hydrocarbon+O_2\rightarrow CO_2+H_2O:  Combustion

4. AB+CD\rightarrow AD+CB : Double displacement

Explanation:

1. Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

Example: Li_2O+CO_2\rightarrow Li_2CO_3  

2. Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Example: Li_2CO_3\rightarrow Li_2O+CO_2

3. Combustion is a type of chemical reaction in which hydrocarbon is reacted with oxygen to form carbon dioxide and water.

Example:  

CH_4+2O_2 \rightarrow CO_2+2H_2O

4. Double displacement reaction is one in which exchange of ions take place.  

Example: NaOH+HCl\rightarrow NaCl+NH_2O

777dan777 [17]3 years ago
6 0

Answer:

Identify the reaction type for each generic chemical equation.

A + B → AB:  synthesis

AB → A + B:  decomposition

Hydrocarbon + O2 → CO2 + H2O:  combustion

AB + CD → AD + CB:   replacement

Explanation:

idk

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A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
A rocket ship is accelerating at 200 m/s2, its mas is 135,000,000 kg. What is the force generated by this acceleration?
Rina8888 [55]

Acceleration does NOT "generate" force.  Acceleration NEEDS force to make it happen.  Without force ... provided by something else ... acceleration can't happen.

The force NEEDED to accelerate a mass with a certain acceleration is

Force needed = (mass) times (acceleration)

For the rocket ship in the question,

Force = (135,000,000 kg) times (200 m/s²)

Force = (135,000,000 x 200) kg-m/s²

<em>Force = 27 Giga-Newtons  </em>(27,000,000,000 Newtons)


The gas-generator cycle F-1 rocket engine, developed in the US by Rocketdyne in the late 1950s, was used in the Saturn V rocket, the main launch vehicle of NASA's Apollo moon lander program .  Five F-1 engines were used in the first stage of each Saturn V.  

==> The thrust of each F-1 engine at full throttle is 7,770 kilo-Newtons.  

It would take <em>3,475 </em>of these F-1 rocket engines, running full-throttle, to provide the force calculated in the answer to this question.  If you didn't have 3,475 F-1 rocket engines, then you couldn't accelerate 135,000,000 kg at 200 m/s².

(And by the way ... the mass of each F-1 engine is 8,400 kg.  So 3,475 engines alone account for 22% of the mass you're trying to accelerate.  And don't even get me started about the mass of the FUEL you'd need to carry.)

5 0
3 years ago
A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
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Answer:

\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

\dfrac{dy}{dt}= 7\ ft/s

y= 14 ft

From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

z=\sqrt{150^2+15^2}

z=150.74 ft

z^2=x^2+y^2

By differentiating with respect to time t

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Here x is constant that is why

\dfrac{dx}{dt}=0

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Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

\dfrac{dz}{dt}=0.65\ ft/s

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The correct answer as the first one above !
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