A because the normal force always acts perpendicular and away from the surface an object is in contact with.
Answer:
Wavelength,
Explanation:
It is given that,
Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz
We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :
c = speed of light
So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.
I am pretty sure that it is protein for both sausage and chicken because most meats are protein.
Answer:
v ’= 21.44 m / s
Explanation:
This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s
f ’= f (v + v₀) / (v-)
where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer
in this exercise both the source and the observer are moving, we will assume that both have the same speed,
v₀ = v_{s} = v ’
we substitute
f ’= f (v + v’) / (v - v ’)
f ’/ f (v-v’) = v + v ’
v (f ’/ f -1) = v’ (1 + f ’/ f)
v ’= (f’ / f-1) / (1 + f ’/ f) v
v ’= (f’-f) / (f + f’) v
let's calculate
v ’= (3400 -3000) / (3000 +3400) 343
v ’= 400/6400 343
v ’= 21.44 m / s
Answer:
a)
b)
c) t = 2.031s X = 1.52m
Explanation:
Let X1 be position of car A as a function of time and X2 be the position of car B as a function of time:
X1 = Xo1 + V1*t If we evaluate this expression at t=t1
S1 = Xo1 + V1*t1 Solving for Xo1 we get its initial position at t=0:
Xo1 = S1 - V1*t1
Similarly for car B:
Xo2 = S2 - V2*t2
Now, to find the instant when car B overtakes car A:
X1 = X2 Replacing their functions in time:
(S1 - V1*t1) + V1*t = (S2 - V2*t2) + V2*t Solving for t:
This is the instant when B reaches A
If we replace this expression in either X1 or X2 expression, we get that position: X1 = X2
If we evaluate these two expressions with the given values:
t = 2.031s and X = 1.52m