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jeka94
3 years ago
8

Question is in the picture below

Physics
1 answer:
Sati [7]3 years ago
4 0

may vary depending on the organization.

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A box is being pulled to the right on flat ground with a force of 112 N at an angle of 42° to the horizontal. What is the x-comp
sasho [114]
The x-component is related with the Force through the trigonometric function cosine.

cos(42°) = x-component / F ⇒ x-component = Fcos(42°) = 112N*0.743 = 83.2 N

4 0
3 years ago
Doug, who runs track for his high school, was challenged to a race by his younger brother, matt. Matt started running first, and
eduard

The speed of Matt is 10 mph.

Doug runs 2 miles an hour faster than Matt, so let Matt’s speed equal x miles per hour. Then Doug’s speed equals x + 2 miles per hour. Each lap is one-quarter of a mile, so Doug runs 1.5 miles in the time it takes Matt to run 1.25 miles.

Rate of Matt is x

Rate of Dough is (x + 2)

Time taken by Matt is 1.25/x

Time taken by Dough is 1.25/(x + 2)

Distance covered by Matt is 1.25

Distance covered by Dough is 1.5

Dough and  Matt  took the same amount of time from the time Doug started, so make an equation by setting the two times in the chart equal to each other, and then solve for x:

            \frac{1.5}{(x + 2)} = \frac{1.25}{x}

              1.5x = 1.25(x + 2)

              1.5x = 1.25x + 2.5

           0.25x = 2.5

                   x = 10

So Matt ran at 10 miles per hour.

To know more about time, speed and distance, visit: brainly.com/question/26046491

#SPJ4

7 0
1 year ago
#1 How fast does an object need to travel to stay in orbit for one second?
fenix001 [56]

19685 mph to stay in orbit or 8 kilometers per second to stay in orbit if this dose not help tell me

8 0
3 years ago
At 0.0 degrees Celsius, a wire cable is 410.0000 meters in length. When the temperature increased to 30.0 degrees Celsius, the w
zzz [600]

Answer: The coefficient of expansion for the wire 0.000028 (^oC)^{-1}.

Explanation:

Original length of the wire = L= 410.0000 m

Initial temperature =T_1=0.0^oC

Final Temperature = T_2=30.0^oC

Increase in Length of the wire = \Delta L=0.3444 m

\frac{\Delta L}{L}=\alpha _{L}\times \Delta T=\alpha _{L}\times (T_2-T_1)

\alpha _L=\frac{\Delta L}{L\times (T_2-T_1)}=\frac{0.3444 m}{410.0000 m\times (30.0^oC-0.0^oC)}

\alpha _L=0.000028 (^oC)^{-1}

The coefficient of expansion for the wire 0.000028 (^oC)^{-1}.

3 0
3 years ago
You can filter the particles out of
Art [367]
A is the answer do ur this question
5 0
3 years ago
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