Answer:
The answer is
A. Pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.
Explanation:
  The question is incomplete, here is a complete question with full options 
You are caulking a window. The caulk is rather thick and, to lay the bead correctly, the exit nozzle is small. A caulking gun uses a plunger which is operated by pulling back on a handle. You must squeeze the handle very hard to get the caulk to come out of the narrow opening because:_________.
A. pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.
B. viscous drag between the walls of the tip and the caulk causes the caulk to swirl around chaotically.
C. Newton’s third law requires most of the energy in the caulk to be used to push back on the plunger rather than moving it through the tip.
D. the high density of the caulk impedes its flow through the small opening.
Since the caulk is thick and the exit nozzle is small, the pressure needed to deliver the caulk will be very high as pressure is uniformly distributed at the plunger side at every part of the caulk, hence very high pressure is needed to deliver the caulk which is why the handle needed the very hard squeeze 
 
        
             
        
        
        
-I believe the star gives off energy-, With<span> most </span>stars<span>, like our sun, hydrogen </span>is<span> being converted into Helium, a process which gives </span>off<span> energy that heats the </span>star<span>.</span>
        
                    
             
        
        
        
Answer:
ثر أنواع التربة خصوبة التربحمراء .
ج- السوداء
Explanation:
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By Boyle's law:
P₁V₁ = P₂V₂
300*75 = P<span>₂*50
</span>P<span>₂*50= 300*75
</span>
P<span>₂ = 300*75/50 = 450
</span>
P<span>₂ = 450 kiloPascals.
The pressure has increased as a result of compression of gas.
Boyle's Law supports this observation.</span>
        
                    
             
        
        
        
Answer:
  v = 344.1 m / s    
  d = 1720.5 m
Explanation:
For this problem we must calculate the speed of sound in air at 22ºC
            v = 331 RA (1+ T / 273)
we calculate
            v = 331 RA (1 + 22/273)
            v = 344.1 m / s
the speed of the wave is constant,
            v = d / t
            d = v t
we calculate
            d = 344.1   5
            d = 1720.5 m