The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.
Answer: Option B
<u>Explanation:
</u>
Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.
So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be
Thus, the amount of work done by two boys will be zero due to their unsuccessful attempt to move a stalled car.
Answer:
B. The elasticity of demand is -0.126
Explanation:
% Change in Quality demand = -2.65% (negative because of drop)
% Change in price = 21%
Elasticity of demand is given by
The Elasticity of demand is -0.12619
First, let's list everything we have...
a = 1.83 m/s^2
F = 1870 N (converted from kN to N)
vi = 0 m/s (it says started from rest, therefore velocity starts at 0)
t = 16 s
1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:
where:
F = force
m = mass
a = acceleration
2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
My guess is A. depth increases because I know that the deeper you go in the ocean, the higher the water pressure is (which makes it difficult to explore).
Answer:
you cant caculate this because there is no question
Explanation:
