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zimovet [89]
3 years ago
5

At room temperature,table salt is a solid and mercury is a liquid.what conclusion can you draw about the melting points of these

substances
Chemistry
2 answers:
never [62]3 years ago
4 0
That table salt has a high melting point and mercury's melting point is low.
Anna007 [38]3 years ago
4 0

Explanation:

It is known that room temperature is the temperature which is equal to 25^{o}C or in kelvin it is equal to 298 K.

Since, room temperature is a low temperature and at this temperature table salt exists as a solid. So, it means that at room temperature there occurs strong intermolecular forces of attraction between the molecules of table salt.

Whereas at room temperature, mercury exists as a liquid. So, there are less strong intermolecular forces of attraction between the molecules of mercury.

This also means that melting point of mercury will be low as it has weak intermolecular forces of attraction as compared to table salt at 25^{o}C.

Therefore, we can conclude that melting point of mercury is less than the melting point of table salt.

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. A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. Th
mafiozo [28]

Answer:

The concentration of CaCl2 in this solution is 0.564 molar (option A)

Explanation:

Step 1: Data given

Mass of CaCl2 = 23.7 grams

Mass of water = 375 grams

Density of solution is 1.05 g/mL

Step 2: Calculate total mass

Total mass = mass of CaCl2 + mass of water

Total mass = 23.7 grams + 375 grams = 398.7 grams

Step 3: Calculate volume of the solution

Density = mass / volume

Volume = mass / density

Volume = 398.7 grams / 1.05 g/mL

Volume = 379.7 mL = 0.3797 L

Step 4: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 23.7 grams / 110.98 g/mol

Moles CaCl2 = 0.214 moles

Step 5: Calculate concentration

Concentration of CaCl2 = moles / volume

Concentration of CaCl2 = 0.214 moles / 0.3797 L

Concentration of CaCl2 = 0.564 mol / L = 0.564 molar

The concentration of CaCl2 in this solution is 0.564 molar (option A)

8 0
4 years ago
Whatmis the frist planet
adoni [48]
The first planet is Mercury
7 0
4 years ago
Read 2 more answers
If a substance goes from the gas phase to the liquid phase, was it heated or cooled
Neporo4naja [7]
When a substance goes from 1 state of matter to a another state of matter, the process is a change of state. What i found out is that it can be heated, whenever the substance goes to another phase i mostly heard, and reasearched that it goes to heated.
4 0
3 years ago
A sample of a hydrocarbon is found to contain 7.48g carbon and 2.52g hydrogen. What is the empirical
Aliun [14]

Answer:

CH₄

Explanation:

To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

Step 1: Determine the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g

Step 2: Calculate the percent by mass of each element

%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%

%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%

Step 3: Divide each percentage by the atomic mass of the element

C: 74.8/12.01 = 6.23

H: 25.2/1.01 = 24.95

Step 4: Divide both numbers by the smallest one, i.e. 6.23

C: 6.23/6.23 = 1

H: 24.95/6.23 ≈ 4

The empirical formula of the hydrocarbon is CH₄.

6 0
4 years ago
What is the % (w/v) concentration of a solution containing 12 grams of solute in 400 ml of solution?
seraphim [82]
Weight/volume  percentage  =  mass of  the  solute/volume  of  solution  x    100

mass of  the   solute=  12grams
volume  of  solution  =  400ml
therefore  %  (w/v)  =  12 /  400  x100  =  3%
8 0
3 years ago
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