Use the following image to answer the following questions. A student was performing an experiment using two identical cups made
of styrofoam. The student had Cup A holding water at 90℃ and Cup B holding water at 20℃. The student then put an Aluminum Bar into each cup that was touching the water. As time passed, the student noticed that the temperature of the water in Cup A and Cup B began to change. Question:
A. Predict what will happen to the temperature of the water in Cup A and Cup B after 1 hour has passed.
B. Explain and give evidence for what type of heat transfer is occurring between the 2 cups.
Whoever answers my question gets brainliest
A. Predict what will happen to the temperature of the water in Cup A and Cup B after 1 hour has passed.
B. Explain and give evidence for what type of heat transfer is occurring between the 2 cups.
Whoever answers my question gets brainliest
1 answer:
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Answer: The volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L
At constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts, then
PV = c
Thus, if the pressure increases, the volume decreases, and if the pressure decreases, the volume increases.
It is not necessary to know the exact value of the constant c to be able to use this law since for a fixed amount of gas at constant temperature, it is satisfied that,
P₁V₁ = P₂V₂
Where P₁ and P₂ as well as V₁ and V₂ correspond to pressures and volumes for two different states of the gas in question.
In this case the first oxygen gas state corresponds to P₁ = 1.00 atm and V₁ = 3.60 L while the second state would be P₂ = 2.50 atm and V₂ = y. Substituting in the previous equation,
1.00 atm x 3.60 L = 2.50 atm x y
We cleared y to find V₂,
V₂ = y = = 1.44 L
Then, <u>the volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L</u>
<u>Answer:</u> The number of moles of weak acid is moles.
<u>Explanation:</u>
To calculate the moles of KOH, we use the equation:
We are given:
Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)
Molarity of the solution = 0.0969 moles/ L
Putting values in above equation, we get:
The chemical reaction of weak monoprotic acid and KOH follows the equation:
By Stoichiometry of the reaction:
1 mole of KOH reacts with 1 mole of weak monoprotic acid.
So, of KOH will react with =
of weak monoprotic acid.
Hence, the number of moles of weak acid is moles.