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Snowcat [4.5K]
3 years ago
5

Question 1(Multiple Choice Worth 4 points) (02.03 LC) A scientist studied four rock fossils that show evolution of the modern-da

y horse dating back to 35 million years, 15 million years, 8 million years, and 1 million years ago. Which rock fossil is most similar to the modern-day horse? 35 million years 15 million years 8 million years 1 million years
Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

The correct answer is 1 millon years.

Explanation:

Fossil rocks serve to study the evolution of species throughout history. Species usually adapt to survive the changing environment around them. Given this fact, we can deduce that the oldest species were very different from the way they are today. This means that the current species are more similar to those that preceded them more recently. The fossil of 1 million years ago is the most similar to today's horse.

Have a nice day!

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The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)
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<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

The expression of K_c for above reaction follows:

K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}         ........(1)

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[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M

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K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4

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\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

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When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

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Now, the equilibrium is shifting to the reactant side. The equation follows:

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial:              0.1      0.1                 0.4       0.1

At eqllm:       0.1+x   0.1+x           0.4-x      0.25-x

Putting values in expression 1, we get:

4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

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Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

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