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Snowcat [4.5K]
3 years ago
5

Question 1(Multiple Choice Worth 4 points) (02.03 LC) A scientist studied four rock fossils that show evolution of the modern-da

y horse dating back to 35 million years, 15 million years, 8 million years, and 1 million years ago. Which rock fossil is most similar to the modern-day horse? 35 million years 15 million years 8 million years 1 million years
Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

The correct answer is 1 millon years.

Explanation:

Fossil rocks serve to study the evolution of species throughout history. Species usually adapt to survive the changing environment around them. Given this fact, we can deduce that the oldest species were very different from the way they are today. This means that the current species are more similar to those that preceded them more recently. The fossil of 1 million years ago is the most similar to today's horse.

Have a nice day!

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Match the following numbers with the correct number of significant digits they possess. Answers may repeat. (4 points)
mezya [45]

(B. 3) 172 All nonzero digits are significant.

(A. 4) 450.0 x 10^3 Trailing zeroes after the decimal point are significant.

(A. 4) 3427 All nonzero digits are significant.

(B. 3) 0.0000455 Leading zeroes are not significant.

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(C. 5) 2205.2 Zeroes between nonzero digits are significant.

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8 0
4 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
4 years ago
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MaRussiya [10]

The balanced dissociation equation for Cs₂CO₃ is:

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A dissociation equation is an equation showing the available ions present in a solution.

To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.

The dissociation equation for Cs₂CO₃ can be written as follow

Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)

Learn more about dissociation equation: brainly.com/question/1903354

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Answer:

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