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Whitepunk [10]
3 years ago
11

HELP PLEASE PLEASE PLEASE

Chemistry
2 answers:
Kitty [74]3 years ago
4 0
I would say b but im not sure
Harrizon [31]3 years ago
3 0
K, so imagine water or ice
when tempurature decreases, it becomes harder and less soluble

so the answer is A
B is when the tempurature rises because the spaces between atoms increases and they are more free to move around and react

answer is A
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For the reaction ?H2 + ?O2 → ?H2O,
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Explanation:

H2O, what is the maximum amount of H2O which could be formed from 10.9 g of H2 and 16.03 g ofO2? Answer in units of g. ... 0.500 mol O2 x 2 mol H2O / 1 mol O2 x 18 g H2O/mol H2O = answer in ..

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3 years ago
3.0 liters= ____quarts<br> 100yards=____mL<br> 50lbs=____kg<br><br> please convert
Alecsey [184]

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100 yards = 764554.858 or 7.646e+7

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Explanation:

hopes this helps :D (can i get brainliest?)

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4 years ago
Imagine you wanted to build a clock with rotating minute and hour hands. Which of the following simple machine of
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Answer:

Wheel and axles

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Clocks run on a complex system of gear trains. This provides the energy to turn the hands of the clock. A high-ratio gear train gears the weight drum way up so that you don't have to rewind the clock very often. This somehow disengages, slips or ratchets the gear train so the clock can be rewound and set.

4 0
3 years ago
When 1.98 g of NaOH (molar mass= 40 g/mole) are added to 75.0 mL of a 0.350 M HCl solution in a coffee-cup calorimeter, the temp
Wittaler [7]

Answer:

(ΔHrxn) = 1.273kJ/mol

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3 0
3 years ago
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0
grandymaker [24]

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of CO_2

\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles

b) moles of H_2O

\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles

6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2

According to stoichiometry :

6 moles of CO_2 require = 6 moles of H_2O

Thus 2.0 moles of CO_2 require=\frac{6}{6}\times 2.0=2.0moles  of H_2O

Thus CO_2 is the limiting reagent as it limits the formation of product.

As 6 moles of CO_2 give =  1 moles of glucose

Thus 2.0 moles of CO_2 give =\frac{1}{6}\times 2.0=0.33moles  of glucose

Mass of glucose = moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

8 0
3 years ago
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