X element can give 3 electrons, and ions X³⁺ can be formed.
Phosphate ion - (PO4)³⁻,
So compound will have formula X³⁺(PO4)³⁻,
XPO4
First, we convert the masses into fractions
<span>138 g of benzene = 1.77 moles benzene
91.2 g of heptane = 0.93 moles heptane
Next, calculate the mole fractions
x1 (benzene) = 1.77 / (1.77 + 0.93) = 0.66
x2 (heptane) = 1 - 0.66 = 0.34
</span>The vapor pressure of pure benzene is 322 torr at 40 C.
At the same temperature, the vapor pressure of heptane is 92 torr.
<span>
The partial pressure of benzene is
p1 = 0.66 (322) = 212.52 torr
The partial pressure of heptane is
p2 = 0.34 (92) = 31.28 torr
</span>
Answer:- 4.36 kPa
Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.
Where the subscripts 1 and 2 are representing initial and final quantities.
From given data:
= 1.049 kPa
= ?
= 7.39 K
= 30.70 K
For final pressure, the equation could also be rearranged as:
Let's plug in the values in it:
= 4.36 kPa
So, the new pressure of the gas is 4.36 kPa.
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