Aluminium reacts with dilute sulfuric acid based on the following reaction:
<span>2Al + 3H2SO4 ..............> Al2 (SO4)3 + 3H2
From the periodic table:
mass of aluminium = 27 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams
mass of sulfur = 32 grams
Therefore:
molar mass of aluminium = 27 grams
molar mass of sulfuric acid = 2(1) + 32 + 4(16) = 98 grams
From the balanced chemical equation:
2 moles of aluminium react with 3 moles of dilute sulfuric acid.
This means that 34 grams of Al react with 294 grams of the acid
To get the amount of aluminium that reacts with </span><span>5.890 g of sulfuric acid, we will do cross multiplication as follows:
</span>amount of Al = (<span>5.890 x 34) / 294 = 0.6811 grams</span>
Answer:
28g
Solution. Hence, 2 moles of nitrogen atoms weigh 28g.
NaCl (Sodium chloride)
LiF (Lithium fluoride)
i just learnt this recently but i need to look through my notes again.
Answer:
The empirical formula of the compound C₃H₆N₂ is C₃H₆N₂
Explanation:
The empirical formula of a compound is the formula of the compound given in the (smallest) whole number ratio of the elements of the compound
The empirical formula of S₂O₂ is SO
The empirical formula of C₃H₆O₃ is CH₂O
The given compound's molecular formula is C₃H₆N₂
The smallest whole number ratio of of the elements of the compound is 3:6:2, therefore, the empirical formula of the compound C₃H₆N₂ is C₃H₆N₂.
