Answer:
the plants it will be bigger if you take care it so much the plant it will help in our world
Explanation:
I HOPE ITS HELP<em>.</em><em>.</em><em>.</em><em>P</em><em>L</em><em>E</em><em>A</em><em>S</em><em>E</em><em> </em><em>C</em><em>O</em><em>R</em><em>R</em><em>E</em><em>C</em><em>T</em><em> </em><em>M</em><em>E</em><em> </em><em>I</em><em>F</em><em> </em><em>I</em><em>M</em><em> </em><em>W</em><em>R</em><em>O</em><em>N</em><em>G</em>
Answer:
A rock is a naturally occurring solid mixture of one or more minerals or organic matter.
Explanation:
A mineral is naturally formed, inorganic, solid, with a fixed chemical composition, and crystalline structure. A rock at the surface of the Earth would need to be weathered down into sediments.
<u>HOPE THIS WILL GIVE YOU SOME IDEAS !!!!!</u>
Answer:
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Option D is correct
Explanation:
Step 1: Data given
Mass of Zinc (Zn) = 50.0 grams
Mass of Hydrogen chloride (HCl) = 50.0 grams
atomic mass Zn = 65.38 g/mol
Molar mass HCl = 36.46 g/mol
Step 2: The balanced equation
Zn + 2HCl → ZnCl2 + H2
Step 3: Calculate moles
Moles = mass / molar mass
Moles Zn = 50.0 grams / 65.38 g/mol
Moles Zn = 0.764 moles
Moles HCl = 50.0 grams / 36.46 g/mol
Moles HCl = 1.37 moles
Step 4: Calculate limiting reactant
For 1 mol Zn we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Zn is in excess. There will react 1.37/2 = 0.685 moles
There will remain 0.764 -0.685 = 0.079 moles
The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.
<h3>How to calculate mass of an element in a compound?</h3>
According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.
This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g
Next, we calculate the percent ratio of each element in the compound; CaSO4.
- Ca = 3.06g/10.4g × 100 = 29.42%
- S = 2.45g/10.4g × 100 = 23.56%
- O = 4.89g/10.4g × 100 = 47.02%
According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:
- Ca = 29.42/100 × 65.8g = 19.36g
- S = 23.56/100 × 65.8g = 15.50g
- O = 47.02/100 × 65.8g = 30.94g
Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.
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mass of carbonic acid = 300g
molar mass of H2CO3 = 2H + C + 3 O
= 2 x 1.008+ 12.01 + 3 x 16
= 62.03g/mol
moles of H2CO3 = mass/Molar mass
= 300/62.03
= 4.8364 moles
1 mole H2CO3 has 3 moles Oxygen
4.8364 moles H2CO3 contains
= 3 x 4.8364 moles Oxygen = 14.509 moles Oxygen
moles = mass/Molar mass
mass of oxygen = moles x Molar mass of Oxygen
= 14.509 x 16
= 232.15g Oxygen
mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g
