Question

In f(x) = 2x^2-8x-10 the y intercept is at and the x intercepts are (-1,0) and

Answer 1

Answer:

see explanation

Step-by-step explanation:

To find the y- intercept let x = 0

f(0) = 0² - 8(0) - 10 = 0 - 0 - 10 = - 10

The y- intercept is (0, - 10)

To find the x- intercepts let f(x) = 0, that is

2x² - 8x - 10 = 0 ( divide through by 2 )

x² - 4x - 5 = 0

Consider the factors of the constant term (- 5) which sum to give the coefficient of the x- term (- 4)

The factors are - 5 and + 1, since

- 5 × 1 = - 5 and - 5 + 1 = - 4, hence

(x - 5)(x + 1) = 0

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

The x- intercepts are (- 1, 0) and (5, 0)