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Minchanka [31]
3 years ago
11

In a 66.0-g aqueous solution of methanol, CH4O, the mole fraction of methanol is 0.290. What is the mass of each component? g

Chemistry
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

23.84g CH30H

32.81g H2O

Explanation:

We will be using the definition of mole fraction to determine the relationship between the number of moles of methanol,

CH3OH , and the number of moles of water.

But mole fraction gives the ratio between the number of moles of a component i of a solution to the total number of moles present in that solution.

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

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Read 2 more answers
Li + HNO3 > LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
2 years ago
Hydrochloric acid (HCl) and sodium hydroxide (NaOH) react to form water and sodium chloride (NaCl). If you have 2.87 g of HCl, 3
wlad13 [49]

Answer:

2.86g

Explanation:

Mass of HCl  = 2.87g

Mass of water  = 3.75g

Mass of NaCl  = 1.98g

Unknown:

Mass of NaOH reacted  = ?

Solution:

  The reaction expression is given as:

           HCl    +   NaOH   →   NaCl   +  H₂O

According to the law of conservation of mass, the mass of reactants and products must be the same.

   Mass of HCl   +   Mass of NaOH  = Mass of NaCl  +  Mass of H₂O

      2.87g + Mass of NaOH  = 1.98g + 3.75g

           Mass of NaOH  = 1.98g + 3.75g - 2.87g  = 2.86g

7 0
3 years ago
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