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Minchanka [31]
3 years ago
11

In a 66.0-g aqueous solution of methanol, CH4O, the mole fraction of methanol is 0.290. What is the mass of each component? g

Chemistry
1 answer:
Juliette [100K]3 years ago
7 0

Answer:

23.84g CH30H

32.81g H2O

Explanation:

We will be using the definition of mole fraction to determine the relationship between the number of moles of methanol,

CH3OH , and the number of moles of water.

But mole fraction gives the ratio between the number of moles of a component i of a solution to the total number of moles present in that solution.

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

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Most of the sulfur used in the United States is chemically synthesized from hydrogen sulfide gas recovered from natural gas well
Rom4ik [11]

Answer:

The rate at which sulfur dioxide is being produced is 0.90 kg/s.

Explanation:

Volume of oxygen gas consumed in second ,V= 994 L

Pressure of the gas = p

Temperature of the gas = T = 170°C= 170 + 273 K=443 K

Moles of oxygen gas consumed in a second = n

PV=nRT ( ideapl gas equation)

n=\frac{PV}{RT}=\frac{0.77 atm\times 994 L}{0.0821 atm L/mol K\times 443 K}

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Moles of dioxygen gas consumed per second = 21.044 mol

2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)   (Claus process)

According to reaction, 3 moles of dioxygen gives 2 moles of sulfur dioxide gas.Then 21.044 moles of dioxygen will give;

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14.029 mol × 64 g/mol = 897.86 g

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Mass of sulfur dioxide produced per second = 0.90 kg

The rate at which sulfur dioxide is being produced is 0.90 kg/s.

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