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3 years ago

Does sulfured food taste different?

Chemistry

2 answers:

Volgvan3 years ago

8 0

Answer:

Yes

Explanation:

Sulfur in its pure do not have any taste and odor but many foods rich in sulfur can have a distinct odor and taste. The foods contains sulfur in very small amounts but some of the foods which are known for rich in sulfur are onion, garlic, egg, flex seeds, walnuts, meat, red bell pepper, cheese, green vegetables etc.

The foods rich in sulfur helps in fighting skin acne and fights skin infection which makes our skin brighter because of this property of sulfur it is used in skin antiseptic creme and medicines.

The intake of the excess sulfur can cause burning sensation, diarrhea, tonsils and even can cause brain damage if taken in too excess and death of the brain cells. So, the sulfur is good for health and is a remedy for our skin if taken by the natural source of food in a healthy amount.

Zinaida [17]3 years ago

4 0

Answer:

He is right, sulfured food dose taste different

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Solid potassium chlorate decomposes upon heating to form

olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

$\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

V2 = $\frac{P1V1T2}{T1P2}$

V2 = 664.1052 ml

245.2 yielded 67.2 molar volume of oxygen

0.66411 will yield = $\frac{245.2 * 0.66411}{67.2}$ = 2.4232 g

percentage of potassium chlorate in the original mixture = $\frac{2.4232 * 100}{7.44}$ = 32.6%

3 0

3 years ago

The equilibrium constant, K, for the following reaction is 1.80x102 at 698 K. 2HI(9) =H2(g) +129) An equilibrium mixture of the

Mrrafil [7]

Explanation:

The equilibrium constant of the reaction = $K_c=1.80\times 10^{-2}$

Initial concentration of HI = 0.311 M

After addition 0.174 mol of HI(g)

Concentration of HI added = $\frac{0.174 mol}{1 L}=0.174 M$

New concentration of HI = 0.311 M + 0.174 M = 0.485 M

$2HI\rightleftharpoons H_2+I_2$

Initial concentration:

0.311 M $4.71\times 10^{-2} M$ $4.71\times 10^{-2} M$

At equilibrium:

(0.485 M - x) $(4.71\times 10^{-2} M+x)$ $(4.71\times 10^{-2} M+x)$

$K_{eq}=\frac{[H_2][I_2]}{[HI]^2}$

$1.80\times 10^{-2}=\frac{(4.71\times 10^{-2} M+x)\times (4.71\times 10^{-2} M+x)}{ (0.485 M-x)^2}$

$\sqrt{1.80\times 10^{-2}}=\frac{(4.71\times 10^{-2} M+x)}{ (0.485 M-x)}$

$0.1342=\frac{(4.71\times 10^{-2} M+x)}{(0.485 M-x)}$

$0.065087 M-0.1342x=4.71\times 10^{-2} M+x$

$0.065087 M-4.71\times 10^{-2} M=1.1342x$

$x=\frac{0.017987 M}{1.3142}=0.01586 M$

Equilibrium concentrations:

$[HI]=0.485 M-x = 0.485 M - 0.01586 M= 0.46914 M$

$[H_2]=[I_2]=4.71\times 10^{-2} M+x=4.71\times 10^{-2} M+0.01586 M$

$[H_2]=[I_2]=0.06296 M$

3 0

3 years ago

The rate of a reaction can be observed by measuring the change in the amount of a reactant over time, as given in the graph belo

Sveta_85 [38]

Looks like exponential decay. Collision theory is consistent with this model because at higher reactant concentrations we expect the reactants to encounter each other more often (collide) and as the concentration decreases we expect fewer and fewer collision events so the rate of reaction becomes less and less.

7 0

4 years ago

andre [41]

Answer:

The correct answer is "A consumer is obtaining carbon by eating carbon-based molecules stored in a producer".

Explanation:

The animal is consuming the carbon present in the molecules stored in the grass. Plants process the carbon present in the soil along with other minerals. The animal, when it feeds on these plants, is consuming the carbon they obtained from the soil. Grasslands are defined largely by their use for grazing, which includes between 10 and 30 percent of soil carbon worldwide.

Have a nice day!

3 0

3 years ago

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What is a giant ball of glowing gas that generates energy by nuclear fusion reaction?

Paladinen [302]

Answer:

sun

Explanation:

3 0

3 years ago